That would of course be the third and only right answer
Answer:
0.08
Step-by-step explanation:
Please use parentheses to indicate which operations must be done first. I 'm choosing to believe that you meant 7^(3x-1) and 5^(x-1).
Taking the common log of both sides, we get:
(3x-1)log 7 = (x-1)log 5
Then 3x·log 7 - log 7 = x log 5 - log 5
Grouping the x terms:
x(3·log 7 - log 5) = log 7 - log 5. We combine log 7 and log 5, obtaining log (7/5).
Then x(3·log 7 - log 5) = log (7/5).
Solving for x:
log (7/5)
x = ---------------------
3·log 7 - log 5
0.1461
x = ------------- = 0.08
1.0363
This agrees with the 3rd answer choice.
Answer:
Step-by-step explanation:
please give me brainlest.
4) Here both smaller and larger triangle is "isosceles" in nature.
So, sum would be 180 with two equal sides.
66 + BDE + BED = 180
2 BDE = 180 - 66
BDE = 114 / 2
BDE = 57
<span>In short, Every four angles would be equal to 57
</span>5) A) 7
It is because it must be smaller than the longest side which is equal to 8
6) D) Yes, Because ∠C is congruent to ∠BED
Hope this helps!
A "Bisector" in Geometry is a line that divides a line into two different or equal parts. It is used on line segments and angles.
The Value of X = angle BCF =90-45 =45.
<h3>What is meant by bisector?</h3>
- A "Bisector" in Geometry is a line that divides a line into two different or equal parts. It is used on line segments and angles.
- The perpendicular bisector theorem deals with congruent triangle segments, allowing for congruent diagonals from the vertices to the circumcenter. The angle bisector theorem, on the other hand, deals with congruent angles, resulting in equal distances from the incenter to the side of the triangle.
- A triangle angle bisector is a line segment that bisects one of the triangle's vertex angles and ends on the opposite side. A triangle's three angle bisectors meet at a single point known as the incenter.
Angle BCD = 90
angle FCD = 45
The Value of X = angle BCF =90-45 =45.
To learn more about : Bisector
Ref : brainly.com/question/11006922
#SPJ13
