You need to calculate 35% of 400.
The way I do this on paper is I split it up into chunks and then add the chunks together.
First I would calculate 10%. To do this, divide 400 by 10, because to get from 100% to 10% you must divide by 10.
So 10% = 40
You need 30%, so you just multiply by 3, because to get from 10% to 30%, you multiply by 3.
So 30% = 120
5% is half of 10% so half of 40 is 20.
So 5% = 20
30% + 5% = 35%
120 + 20 = 140
So they had traveled 140 miles when Joshua fell asleep. Hope this helps :)
Recall the fundamental rule of trig:
![\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}](https://tex.z-dn.net/?f=%5Csin%5E2%28x%29%2B%5Ccos%5E2%28x%29%3D1%20%5Cquad%5Cforall%20x%20%5Cin%20%5Cmathbb%7BR%7D)
So, there exists an angle
such that
![(0.6,0.35)=(\sin(t),\cos(t))](https://tex.z-dn.net/?f=%280.6%2C0.35%29%3D%28%5Csin%28t%29%2C%5Ccos%28t%29%29)
if and only if
![\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1](https://tex.z-dn.net/?f=%5Csin%5E2%28t%29%2B%5Ccos%5E2%28t%29%3D0.6%5E2%2B0.35%5E2%3D1)
Working out the numbers, we get
![0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1](https://tex.z-dn.net/?f=0.6%5E2%2B0.35%5E2%3D0.36%2B0.1225%3D0.4825%5Cneq%201)
So, there doesn't exist a number
such that
![(0.6,0.35)=(\sin(t),\cos(t))](https://tex.z-dn.net/?f=%280.6%2C0.35%29%3D%28%5Csin%28t%29%2C%5Ccos%28t%29%29)
D shows equivalent expressions
(33/7) / (1 13/14)
= (33/7)/ (27/14)
= (33/7)* (14/27)
= 22/9
= 2 4/9
The final answer is 2 4/9~
Answer:
Hey, just here so he can get brainliest, have a nice day!
Step-by-step explanation: