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3 years ago

8(x - 1) - 4 = 4(2x - 3)

Mathematics

1 answer:

nordsb [41]3 years ago

6 0

Answer:

All real numbers.

Step-by-step explanation:

8x-8-4=8x-12

8x-12=8x-12

All real numbers

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SOMEONE HELP ME PLEASE WITH THESE PROBLEMS AND PLEASE SHOW YOUR WORK FOR 50 points and BRAINLIEST THANK YOU

ELEN [110]

<u>Answer</u>:

13. $6x^7 y^7$ || 14. $\frac{25x^4}{y^6}$

<u>explanation</u>:

13.

$\frac{12x^9 y^5}{2x^2 y^-2}$

$6x^{9-2} y^{5--2}$

$6x^7 y^7$

14.

$(\frac{5y^{-3} }{x^{-2} } )^{2}$

$(\frac{5y^{-3} }{x^{-2} } )(\frac{5y^{-3} }{x^{-2} } )$

$\frac{\frac{25}{y^6}}{\left(x^{-2}\right)^2}$

$\frac{\frac{25}{y^{-6} }}{\left(x^{-4}\right)}$

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Llana [10]

Answer:

1. $x^{2} + x^{2} + (10\cdot x) \cdot (4)$

Step-by-step explanation:

(This exercise is written in Spanish and therefore explanation will be held in such language)

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El cual corresponde con la opción 1.

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$cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}$

$\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}$

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Answer:

Step-by-step explanation:

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