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2 years ago

Please help me please help me if you don't know gently move your hand

Mathematics

1 answer:

Zinaida [17]2 years ago

8 0

Answer:

Diameter: 4km

Radius: 2km (divide diameter by two)

Circumference Formula: c = dπ or c = 2rπ

Circumference Value = 4π or 2(2π)

(the actual answer is 12.56, just do the math)

Step-by-step explanation:

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Question 1 of 10

kvasek [131]

Given:

A parabola opens up or down and its vertex is at the point (h, v).

To find:

The equation of the parabola.

Solution:

A parabola opens up or down. It means it is a vertical parabola.

The vertex form of a vertical parabola is

$y=a(x-h)^2+k$ ...(i)

Where, a is constant and (h,k) is vertex.

The vertex of given parabola is at point (h,v). Putting h=h and k=v in (i), we get

$y=a(x-h)^2+v$

The required equation of the parabola is $y=a(x-h)^2+v$ .

Therefore, the correct option is A.

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2 years ago

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Earth is 92,955,820 miles from the sun, Mars is 142,633,260 miles from the sun. What is the distance the martians would have to

Maru [420]

For martians to destroy human society, they would need to travel 49,667,440 miles.

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2 years ago

Arrange the digits 1,2,3,4,5,6,7 so that when the numbers are added up, they will total 100.

GuDViN [60]

36 + 57 + 4 + 2 + 1 = 100 would do it.

6 0

2 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

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2 years ago

HELP ASAP WILL MARK AS BRAINILEST TO WHOEVER GETS IT RIGHT

mixas84 [53]

The correct answer is B. For sure it is. It took a while to solve in my head

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2 years ago