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3 years ago

Find the slope of the line passing through the points (1, -4) and (3, -1)

Mathematics

1 answer:

Olin [163]3 years ago

4 0

E 3/2. I graphed it:).

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A bag of marbles had 18 green marbles and the rest were blue. For a game, 5/6 of the 18

stepan [7]

Answer:

A 5 B 2 C3

Step-by-step explanation:

6 0

4 years ago

Multiple choices answer and explain the solution?

Oksi-84 [34.3K]

Answer:

associative property of multiplication

Step-by-step explanation:

You cant rlly explain, you just have to know your properties

7 0

3 years ago

Last month, 17 people showed up to help a local charity. This month, 55 people volunteered. What is the percentage increase?

astra-53 [7]

Step-by-step explanation:

The formula for percent change is

change/original.

So let's subtract 17 from 55 to find the change. 55-17=38

This is the change. Now we divide it by the original, 17.

38/17=2.235294

We're not done yet! We have to move the decimal point over to the right 2 spaces to make it a percentage. So, the percentage increase is

about 223.53 percent

6 0

3 years ago

A rectangle measures 15 1/4 feet by 8 11/15 feet. If the length and width are extended by 1 2/3 Feet each find the area of the n

zubka84 [21]

Answer:

New area is 175 42/45 feet ²

Step-by-step explanation:

Given data

Length l= 15 1/4

To proper fraction = 61/4 feet

Width w= 8 11/15

To proper fraction = 131/15 feet

Extention = 1 2/3

To proper fraction = 5/3

Dimensions of new rectangle

Length =61/4+5/3 = 183+20/12

LCM = 12 = 203/12

Width = 131/15+5/3= 131+25/15

LCM = 15 = 156/15

Area = 203/12*156/15= =31668/180

=31668/180

= 7917/45

= 175 42/45 feet ²

6 0

3 years ago

Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0

cestrela7 [59]

When $n=0$ , you have

$4^0=1\equiv3(0)+1=1\mod9$

Now assume this is true for $n=k$ , i.e.

$4^k\equiv3k+1\mod9$

and under this hypothesis show that it's also true for $n=k+1$ . You have

$4^k\equiv3k+1\mod9$
$4\equiv4\mod9$
$\implies 4\times4^k\equiv4(3k+1)\mod9$
$\implies 4^{k+1}\equiv12k+4\mod9$

In other words, there exists $M$ such that

$4^{k+1}=9M+12k+4$

Rewriting, you have

$4^{k+1}=9M+9k+3k+4$
$4^{k+1}=9(M+k)+3k+3+1$
$4^{k+1}=9(M+k)+3(k+1)+1$

and this is equivalent to $3(k+1)+1$ modulo 9, as desired.

3 0

4 years ago