Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
of their perimeters is equal to the ratio of their corresponding side lengths. ratio of their areas is equal to the square of the ratio of their corresponding side lengths.
Answer:
y = -12x + 3
Step-by-step explanation:
The slope-intercept form of an equation can be written as y = mx + b where m is the slope and b is the y-intercept. We are given both values, so we can plug them into the equation to get:
y = mx + b
y = -12x + 3
The answer is 45
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