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3 years ago

Can I see detailed calculation for Dash?

Mathematics

1 answer:

egoroff_w [7]3 years ago

8 0

I think you can, sorry if i’m wrong

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Roger drives 256km and uses 20l of fuel. what is his average fuel consumption for 100km?

Bezzdna [24]

Answer:

7. 8125 l

Step-by-step explanation:

256 km ....... 20l

100 km ...........x l

x = 100×20/256

= 7. 8125 l

3 0

3 years ago

If the Internet consisted of four computers, there would be six possible connections. If it consisted of five computers, there w

Luba_88 [7]

Answer:

45 possible connections

Step-by-step explanation:

The general equation for finding the possible number of connections in a network is given as

$\frac{n*(n - 1)}{2}$

where n is the number of computers on the network.

for 4 computers, we'll have

$\frac{4*(4 - 1)}{2}$ = $\frac{4*3}{2}$ = 6

for 5 computers, we'll have

$\frac{5*(5 - 1)}{2}$ = $\frac{5*4}{2}$ = 10.

therefore, for 10 computers, we will have

$\frac{10*(10 - 1)}{2}$ = $\frac{10*9}{2}$ = 45 possible connections

3 0

3 years ago

Use the given numbers above the table in multiplying integers and to fill in the blanks inside the box.

Jet001 [13]

Answer:

Step-by-step explanation:

1 × 5 = 5

(- 2) × (- 3) = 6

4 × (- 6) = - 24

I hope I've helped you.

8 0

3 years ago

Read 2 more answers

Monthly spending : $46,$62,$63,$57,$50$42$56$40 its median, mode and range

ozzi

Mean = $52
median = $53
no mode
range = 63 - 40 = $23

6 0

3 years ago

RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly

tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

$C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120$

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0

3 years ago