Answer:
16.87 m/s
Explanation:
To find the speed of the car at the top, when the normal force is equal the gravitational force, we just need to equate both forces:
is the centripetal acceleration in the loop:
So we have that:
So, using the gravity = 9.81 m/s^2 and the radius = 29 meters, we have:
The speed of the car is 16.87 m/s at the top.
Answer:
37.5 N Hard
Explanation:
Hook's law: The force applied to an elastic material is directly proportional to the extension provided the elastic limit of the material is not exceeded.
Using the expression for hook's law,
F = ke.............. Equation 1
F = Force of the athlete, k = force constant of the spring, e = extension/compression of the spring.
Given: k = 750 N/m, e = 5.0 cm = 0.05 m
Substitute into equation 1
F = 750(0.05)
F = 37.5 N
Hence the athlete is pushing 37.5 N hard
I believe it is B, the object that reflects a lot of light, absorbs a little light, and transmit almost no light.
Do you see that blank, open space after the word "potential ..." ?
There's supposed to be a number there that actually tells us the value of the potential. Without that number ... and a lot more description of the whole scenario here ... there's no possible answer to the question.
If E = 1/2 * m * v^2
v = (2E/m)^1/2
so the larger the mass, the higher the velocity hence taylor is moving faster
