so to increase Ue by 16 times you gotta reduce R(distence) by 16 times
Answer:
A. force
Explanation:
Magnetism is a type of force.
Answer:
a)
Explanation:
- A block sliding down an inclined plane, is subject to two external forces along the slide.
- One is the component of gravity (the weight) parallel to the incline.
- If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:
(taking as positive the direction of the movement of the block)
- The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
- When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:
- The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:
- In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:
- As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
- In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:
Answer:
v = 16.23 m/s²
Explanation:
In the problems that have friction force this must be included in the energy conservation equation, in these cases the friction force performs dissipative work that is equal to the decrease in mechanical energy
= -
Let's look for the initial mechanical energy
= Ke = ½ k x²
Final energy
= K + U = ½ m v² + mg y
The work of the rubbing force is
= - fr d.
Let's look for the missing terms, let's start with the amount the spring compresses, let's use Hooke's law
F = - k x
x = F / k
x = 4400/1100
x = 4 m
Let's write the equation and calculate
-Fr d = (1/2 m v² + ½ mg y) - ½ k x²
½ m v² = -fr .d + 1 / 2k x² - ½ m g y
v² = 2/m (- fr .d + 1/2 k x² - ½ m g y)
v² = 2/60 (-40 4 + ½ 1100 4² - ½ 60 9.8 2.5)
v = √(7905/ 30)
v = 16.23 m/s²