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Ann [662]
2 years ago
13

If the moon is a full moon tonight what will be the moon one week later waxing or waning

Physics
1 answer:
tatiyna2 years ago
5 0

-- Starting from nothing (New Moon), the moon's shape grows ('waxes')
for half of the cycle, until it's full, and then it shrinks ('wanes') for the next
half of the cycle.

-- The moon's complete cycle of phases runs 29.53 days . . . roughly
four weeks.

-- So, beginning from New Moon, it spends about two weeks waxing until
it's full, and then another two weeks waning until it's all gone again.
 
-- After a Full Moon, the moon is waning for the next two weeks.  So it's
definitely <em>waning</em> at <em><u>one week</u></em> after Full.


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Water has a mass per mole of 18.0 g/mol, and each water molecule (H20) has 10 electrons. (a) How many electrons are there in one
Allushta [10]

Answer:

total number of electron in 1 litter is 3.34 × 10^{26} electron

Explanation:

given data

mass per mole = 18 g/mol

no of electron = 10

to find out

how many electron in 1 liter of water

solution

we know molecules per gram mole is 6.02 ×10^{23} molecules

no of moles is 1

so

total number of electron in water is = no of electron ×molecules per gram mole × no of moles

total number of electron in water is = 10 × 6.02 ×10^{23} × 1

total number of electron in water is = 6.02×10^{24} electron

and

we know

mass = density × volume    ..........1

here we know density of water is 1000 kg/m

and volume = 1 litter = 1 × 10^{-3} m³

mass of 1 litter = 1000 × 1 × 10^{-3}

mass = 1000 g

so

total number of electron in 1 litter =  mass of 1 litter × \frac{molecules per gram mole}{mass per mole}

total number of electron in 1 litter =  1000 × \frac{6.02*10{24}}{18}

total number of electron in 1 litter is 3.34 × 10^{26} electron

8 0
3 years ago
A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc
ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

T=2\pi \sqrt{\frac{L}{g} }

Where T is period

           L is length of rod

       g is acceleration due to gravity =     9.8m/s^{2}

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this L_{O}

L_{O} = 3/4 * 5.95m

        = 4.4625m

thus   T=2\pi \sqrt{\frac{L_{O} }{g} }

          T=2\pi \sqrt{\frac{4.4625 }{9.8} }

          T= 4.24sec

8 0
3 years ago
Explain why a doctor might not give you any medication if you have a viral disease?
fomenos

Answer:

You never know if the medication could make you worse

Explanation:

5 0
3 years ago
Read 2 more answers
according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains
Licemer1 [7]

Answer:

The Acceleration will increase

Explanation:

Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.

It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

4 0
3 years ago
A train accelerates to a velocity of 500 m/s over time of 2s. The acceleration it experienced was 50m/s2. What was its initial v
ValentinkaMS [17]

Explanation:

We know ,

  • v = u + at
  • u = v - at
  • u = 500 - 2*50
  • u = 400 m/s
7 0
3 years ago
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