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il63 [147K]
3 years ago
6

Can anyone please help me with this geometry question!!

Mathematics
1 answer:
kondaur [170]3 years ago
7 0

Answer:

-5° < x < 26°

Step-by-step explanation:

The given parameters are;

The length of the rays forming the 62° = The length of the rays forming the 2·x + 10°

The length of the side opposite the 62° = 15

The length of the side opposite the 2·x + 10° angle = 14

Therefore, by construction, we have;

2·x + 10° < 62°

2·x  < 62° - 10°

2·x  < 52°

x < 52°/2

x < 26°

Also, we have that the angle 2·x + 10°  is real, therefore;

0 < 2·x + 10°

-5 < x

Which gives;

-5° < x < 26°.

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k = 3

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Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\

(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2

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16 =  (7-k)^2

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Answer:

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