<span>Exactly 4(4 - 2*2^(1/3) + 2^(2/3)) feet,
or approximately 12.27023581 feet.
Let's first create an equation to calculate the relative intensity of the light based upon the distance D from the brighter light source. The distance from the dimmer light source will of course be (20-D). So the equation will be:
B = 4/D^2 + 1/(20-D)^2
The minimum and maximum can only occur at those points where the slope of the equation is 0. And you can determine the slope by using the first derivative. So let's calculate the first derivative.
B = 4/D^2 + 1/(20-D)^2
B' = d/dD [ 4/D^2 + 1/(20-D)^2 ]
B' = 4 * d/dD [ 1/D^2 ] + d/dD [ 1/(20-D)^2 ]
B' = 4(-2)D^(-3) + (-2)(20 - D)^(-3) * d/dD [ 20-D ]
B' = -8/D^3 - 2( d/dD [ 20 ] - d/dD [ D ] )/(20 - D)^3
B' = -8/D^3 - 2(0 - 1)/(20 - D)^3
B' = 2/(20 - D)^3 - 8/D^3
Now let's find a zero.
B' = 2/(20 - D)^3 - 8/D^3
0 = 2/(20 - D)^3 - 8/D^3
0 = 2D^3/(D^3(20 - D)^3) - 8(20 - D)^3/(D^3(20 - D)^3)
0 = (2D^3 - 8(20 - D)^3)/(D^3(20 - D)^3)
0 = 2D^3 - 8(20 - D)^3
8(20 - D)^3 = 2D^3
4(20 - D)^3 = D^3
4(8000 - 1200D + 60D^2 - D^3) = D^3
32000 - 4800D + 240D^2 - 4D^3 = D^3
32000 - 4800D + 240D^2 - 5D^3 = 0
6400 - 960D + 48D^2 - D^3 = 0
-6400 + 960D - 48D^2 + D^3 = 0
D^3 - 48D^2 + 960D - 6400 = 0
We now have a simple cubic equation that we can use the cubic formulas to solve.
Q = (3*960 - (-48)^2)/9 = 64
R = (9*(-48)*960 - 27*(-6400) - 2*(-48)^3)/54 = -384
D = Q^3 + R^2 = 64^3 + (-384)^2 = 409600
Since the value D is positive, there are 2 imaginary and 1 real root. We're only interested in the real root.
S = cbrt(-384 + sqrt(409600))
S = cbrt(-384 + 640)
S = cbrt(256)
S = 4cbrt(4)
T = cbrt(-384 - sqrt(409600))
T = cbrt(-384 - 640)
T = cbrt(-1024)
T = -8cbrt(2)
The root will be 4cbrt(4) - 8cbrt(2) + 48/3
So simplify
4cbrt(4) - 8cbrt(2) + 48/3
=4cbrt(4) - 8cbrt(2) + 16
=4(cbrt(4) - 2cbrt(2) + 4)
= 4(4 - 2*2^(1/3) + 2^(2/3))
Which is approximately 12.27023581
This result surprises me. I would expect the minimum to happen where the intensity of both light sources match which would be at a distance of 2/3 * 20 = 13.3333 from the brighter light source. Let's verify the calculated value.
Using the brightness equation at the top we have:
B = 4/D^2 + 1/(20-D)^2
Using the calculated value of 12.27023581, we get
B = 4/D^2 + 1/(20-D)^2
B = 4/12.27023581^2 + 1/(20-12.27023581)^2
B = 4/12.27023581^2 + 1/7.72976419^2
B = 4/150.5586868 + 1/59.74925443
B = 0.026567713 + 0.016736611
B = 0.043304324
And the intuition value of 13.33333333
B = 4/D^2 + 1/(20-D)^2
B = 4/13.33333333^2 + 1/(20-13.33333333)^2
B = 4/13.33333333^2 + 1/6.666666667^2
B = 4/177.7777778 + 1/44.44444444
B = 0.0225 +0.0225
B = 0.045
And the calculated value is dimmer. So intuition wasn't correct.
So the object should be placed 4(4 - 2*2^(1/3) + 2^(2/3)) feet from the stronger light source, or approximately 12.27023581 feet.</span>
Im not 100% sure, but I think the answer is C. If not, Im sorry for bothering you.
Answer: I believe it is B
The change in temperature had the greatest effect at changing the volume of the balloon.
<h3>What are the gas laws?</h3>
The gas laws are used to describe the parameters that has to do with gases.
Given that;
P1 = 98.5 kPa
T1 = 18oC or 291 K
V1 = 74.0 dm3
P2 = 7.0 kPa
V2 = ?
T2 = 18oC or 291 K
P1V1/T1 = P2V2/T2
P1V1T2 =P2V2T1
V2= P1V1T2/P2T1
V2 = 98.5 kPa * 74.0 dm3 * 291 K/ 7.0 kPa * 291 K
V2 = 1041.3 dm3
When;
V1 = 1041.3 dm3
T1 = 291 K
V2 = ?
T2 = 80oC or 353 K
V1/T1 = V2/T2
V1T2 = V2T1
V2 = V1T2/T1
V2 = 1041.3 dm3 * 353 K/291 K
V2 = 1263 dm3
The change in temperature had the greatest effect at changing the volume of the balloon.
Given that
V1 = 100 cm^3
T1 = 273 K
P1 = 1.01 * 10^5 Pa
V2 = ?
P2 = 3.00 x 10^-4 Pa
T2 = -180oC or 255 K
V2= P1V1T2/P2T1
V2 = 1.01 * 10^5 Pa * 100 cm^3 * 255 K / 3.00 x 10^-4 Pa * 273 K
V2 = 3.14 * 10^10 cm^3
Learn more about gas laws:brainly.com/question/12669509
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