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2 years ago

What’s the SI unit of the amount of isopropyl alcohol in a beaker?

Chemistry

1 answer:

Illusion [34]2 years ago

7 0

Answer:

mole

Explanation:

The mole in chemistry is used to represent the amount of any substance. Just like quantifying everyday things like a dozen, score, gross etc, it is a convenient unit of quantity of particles. A mole denotes 6.02 x 10²³particles of a susbstance.

Therefore, a mole is the standard unit(SI) for the amount of isopropyl alcohol in a beaker.

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This turbine was mostly installed because wind power ?.......

Montano1993 [528]

Answer:

Wind turns the propeller-like blades of a turbine around a rotor, which spins a generator, which creates electricity.

Explanation:

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3 years ago

un estudiante introduce un corcho cuya densidad es 0.95 g/cm en cada uno de los liquidos que figura representa mejor la situacio

bagirrra123 [75]

Answer:

La respuesta correcta es la opción A.

Explicación:

La densidad del corcho es 0.95g / cm3 por lo que se hundirá en la solución de acetona porque el corcho es más denso que la solución de acetona mientras que por otro lado, el corcho flotará en otros dos líquidos porque la densidad del corcho es menor que en otros dos líquidos o, en otras palabras, los dos líquidos son más densos que el corcho, por eso el corcho flotará en estos dos líquidos.

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3 years ago

a sample of hydrogen gas (h2) is mixed with water vapor (h2o (g)). the make sure has a total pressure of 811 torr, and the water

Alborosie

Answer:

$n=0.430molH_2$

Explanation:

Hello!

In this case, considering the partial Dalton's law of partial pressures, we can notice that the total pressure equals the pressure of steam and the pressure of hydrogen, which can be determined as shown below:

$p_T=p_H+p_w\\\\p_H=811torr-12torr=799torr*\frac{1atm}{760torr}\\\\p_H=1.05atm$

Thus, by using the ideal gas law, we can compute the moles of hydrogen as shown below:

$PV=nRT\\\\n= \frac{PV}{RT}=\frac{1.05atm*10.0L}{0.082\frac{atm*L}{mol*K}*298K}\\\\n=0.430molH_2$

Best regards!

6 0

3 years ago

George has a mass of 65kg. What would George weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)

dem82 [27]

Answer:

$\boxed{\large \text{104 N}}$

Explanation:

$\text{Weight} = \text{65 kg} \times \dfrac{\text{1.6 N}}{\text{1 kg}} = \textbf{104 N}\\\\\text{George would weigh $\boxed{\large \textbf{104 N}}$ on the moon}$

5 0

2 years ago

Read 2 more answers

I have 345mL of a 1.5M NaCl solution. If I boil the water until the volume of the solution is 250mL, what will the molarity of t

Karo-lina-s [1.5K]

Answer is
C. 2.07 M

For explanation

M1V1 = M2V2

M2 = (M1V1)/V2

M2 = (1.5M x 345ml) / 250 ml

:. M2 = 2.07 M

8 0

3 years ago