First you add 87 +89 which equals 176.
second you multiply all the numbers you want to divide, which, to save time, equals 69,120
176 / 69,120 = 0.0025462962963 (0.003 if needing to round)
Answer:
Step-by-step explanation:
We have given:
-2x+y=4 ---------equation1
3x+4y=49 ---------equation 2
We will solve the 1st equation for y and substitute the value into the 2nd equation.
-2x+y=4 ---------equation1
Move the values to the R.H.S except y
y = 2x+4
Now substitute the value of y in 2nd equation:
3x+4y=49
3x+4(2x+4)=49
3x+8x+16=49
Combine the like terms:
3x+8x=49-16
11x=33
Now divide both the sides by 11
11x/11 = 33/11
x= 3
Now substitute the value of x in any of the above equations: We will substitute the value in equation 1:
-2x+y=4
-2(3)+y=4
-6+y=4
Combine the constants:
y=4+6
y = 10
Thus the solution set of (x,y) is {(3,10)}....
Answer:
45°, 45°, 90°
Step-by-step explanation:
Find the vectors to represent each sides
AB =<3-1, 6-0>=<2,6>
AC = < -1-1, 4 - 0 > = < -2, 4>
Magnitude of the vectors
AB = √(2²+6²) = 6.32
AC = √ ((-2)² + 4²) = 4.47
cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504
θ = arcos(20 / 28.2504 ) approx = 45°
Magnitude of the vectors
BA =<1-3,0-6>=<-2,-6>
BC =<-1-3,4-6>=<-4,-2>
Magnitude of the vectors equals
BA = √((-2)² + (-6)²) = 6.325
BC = √((-4)² + (-2)²) = 4.4721
cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286
θ = arcos (20 / 28.286 ) = 45°
Magnitude of the vectors
CB =<3--1, 6-4>=<4,2>
CA=<1--1,0-4>=<2,-4>
Magnitude of the vector =
CB = √(4² + 2²) = 4.4721
CA = √(2² + (-4)²) = 4.4721
cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0
θ = arcos 0 = 90°
Answer:
5.52 miles
Step-by-step explanation:
All you need to do in multiply 1.2 by 4.6 like this:
1.2 x 4.6 = 5.52 miles
I hope this helps
Answer:
£5.10
Step-by-step explanation:
10% of £34 is £3.40
5% of £34 is £1.70
£3.40 + £1.70 = £5.10
