Please help find the answer below.

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

Answer:

"The interquartile range for the two sets of data are the same"

Step-by-step explanation:

This is a box and whisker plot.

The rectangular box, left-most side is Quartile 1.

Right-most side is Quartile 3.

The middle line is Quartile 2, or mean.

Now, the inter quartile range is the difference in 3rd and 1st quartiles.

So,

IQR = Q3 - Q1

For School #1:

IQR = 86 - 76 = 10

For School #2:

IQR = 90 - 80 = 10

Hence, the IQR is same for both data set.

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For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0

3 years ago

(2y+1.6)/0.8=30/2.5 Please Help! Solve for Y

galina1969 [7]

y = 4

first note that the right side simplifies to 12, equation can be written

$\frac{2y+1.6}{0.8}$ = 12 ( multiply both sides by 0.8 )