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3 years ago

Find end and mid point

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

4 0

Answer:

You already post your answer!

Step-by-step explanation:

Maybe you should get two points in order to find midpoint and endpoint!

or you should give other information!

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PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

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3 years ago

Choose a true statement.

madreJ [45]

Answer: c

Step-by-step explanation:

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3 years ago

What is a solution to (x + 6)(x + 2) = 60?

Elden [556K]

Answer:

Ox=4

Step-by-step explanation:

expand he equation

x²+8x-48=0

using substitution method (of the options)

4 substituted as X eliminates all an results to zero

16+32-48=0

please mark brainliest

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3 years ago

Solve the compound inequality 8x > –32 or 6x ≤ –48.

Korvikt [17]

Answer:

x>-4 x≤-8

Step-by-step explanation:

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3 years ago

Help plz solve these equations by completing the square x square + 12x =1

Hitman42 [59]

Answer:

x = - 6 ± $\sqrt{37}$

Step-by-step explanation:

Given

x² + 12x = 1

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(6)x + 36 = 1 + 36

(x + 6)² = 37 ( take the square root of both sides )

x + 6 = ± $\sqrt{37}$ ( subtract 6 from both sides )

x = - 6 ± $\sqrt{37}$ ← exact solutions

3 0

3 years ago