1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
agasfer [191]
3 years ago
5

7. After boiling, the 18 liters of water was reduced to 7 liters. How many water was

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Sorry if its wrong bro

You might be interested in
Solve the system of equations. please help asap! i appreciate it!
Natasha_Volkova [10]

Answer:

B. (-1, 2) and (4,7)

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

5 0
3 years ago
Read 2 more answers
Given: f(a)= a³ +a and g(a) = a -1 Find: (fog)(a)​
Anvisha [2.4K]

Answer:

(fog)(a)​ = a³ - 3a² + 4a - 2

           = (a - 1)×(a² - 2a + 2)

Step-by-step explanation:

<u><em>Given</em></u> :

g(a) = a -1 

f(a)= a³ +a

…………………………

(fog)(a)​ = f(g(a)​))

           = g(a)³ + g(a)

           = (a - 1)³ + (a - 1)

           = (a³ - 3a² + 3a - 1) + (a - 1)

           = a³ - 3a² + 3a - 1 + a - 1

           = a³ - 3a² + 3a + a - 1 - 1

           = a³ - 3a² + 4a - 2

<u><em>Second method</em></u> :

(fog)(a)​ = f(g(a)​))

           = f(a - 1)

           = (a - 1)³ + (a - 1)

           = (a - 1)×[(a - 1)² + 1]

           = (a - 1)×[a² - 2a + 1 + 1]

           = (a - 1)×(a² - 2a + 2)

4 0
2 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
FromTheMoon [43]

Answer:

The Taylor series is \ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

The radius of convergence is R=3.

Step-by-step explanation:

<em>The Taylor expansion.</em>

Recall that as we want the Taylor series centered at a=3 its expression is given in powers of (x-3). With this in mind we need to do some transformations with the goal to obtain the asked Taylor series from the Taylor expansion of \ln(1+x).

Then,

\ln(x) = \ln(x-3+3) = \ln(3(\frac{x-3}{3} + 1 )) = \ln 3 + \ln(1 + \frac{x-3}{3}).

Now, in order to make a more compact notation write \frac{x-3}{3}=y. Thus, the above expression becomes

\ln(x) = \ln 3 + \ln(1+y).

Notice that, if x is very close from 3, then y is very close from 0. Then, we can use the Taylor expansion of the logarithm. Hence,  

\ln(x) = \ln 3 + \ln(1+y) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{y^n}{n}.

Now, substitute \frac{x-3}{3}=y in the previous equality. Thus,

\ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

<em>Radius of convergence.</em>

We find the radius of convergence with the Cauchy-Hadamard formula:

R^{-1} = \lim_{n\rightarrow\infty} \sqrt[n]{|a_n|},

Where a_n stands for the coefficients of the Taylor series and R for the radius of convergence.

In this case the coefficients of the Taylor series are

a_n = \frac{(-1)^{n+1}}{ n3^n}

and in consequence |a_n| = \frac{1}{3^nn}. Then,

\sqrt[n]{|a_n|} = \sqrt[n]{\frac{1}{3^nn}}

Applying the properties of roots

\sqrt[n]{|a_n|} = \frac{1}{3\sqrt[n]{n}}.

Hence,

R^{-1} = \lim_{n\rightarrow\infty} \frac{1}{3\sqrt[n]{n}} =\frac{1}{3}

Recall that

\lim_{n\rightarrow\infty} \sqrt[n]{n}=1.

So, as R^{-1}=\frac{1}{3} we get that R=3.

8 0
4 years ago
F is a twice differentiable function that is defined for all reals. The value of f "(x) is given for several values of x in the
nadezda [96]

The correct answer is actually the last one.

The second derivative f''(x) gives us information about the concavity of a function: if f''(x) then the function is concave downwards in that point, whereas if f''(x)>0 then the function is concave upwards in that point.

This already shows why the first option is wrong - if the function was concave downwards for all x, then the second derivate would have been negative for all x, which isn't the case, because we have, for example, f''(8)=5

Also, the second derivative gives no information about specific points of the function. Suppose, in fact, that f(x) passes through the origin, so f(0)=0. Now translate the function upwards, for example. we have that f(x)+k doesn't pass through the origin, but the second derivative is always f''(x). So, the second option is wrong as well.

Now, about the last two. The answer you chose would be correct if the exercise was about the first derivative f'(x). In fact, the first derivative gives information about the increasing or decreasing behaviour of the function - positive and negative derivative, respectively. So, if the first derivative is negative before a certain point and positive after that point. It means that the function is decreasing before that point, and increasing after. So, that point is a relative minimum.

But in this exercise we're dealing with second derivative, so we don't have information about the increasing/decreasing behaviour. Instead, we know that the second derivative is negative before zero - which means that the function is concave downwards before zero - and positive after zero - which means that the function is concave upwards after zero.

A point where the function changes its concavity is called a point of inflection, which is the correct answer.

7 0
3 years ago
How to divide fractions
Marina86 [1]
Leave the first fraction in the equation alone.
Turn the division sign into a multiplication sign.
Flip the second fraction over (find its reciprocal).
Multiply the numerators (top numbers) of the two fractions together. ...
Multiply the denominators (bottom numbers) of the two fractions together.
6 0
3 years ago
Other questions:
  • Whats the difference in 7-2 5/8
    14·2 answers
  • The figure is formed from rectangles. Find the total area.
    5·1 answer
  • Jenny washed dishes 4 times as many asher brother last month
    14·1 answer
  • I need the quadratic formula.​
    10·2 answers
  • There are (n r) different linear arrangements of n balls of which r are black and n-r are white. give a combinatorial explanatio
    8·1 answer
  • 40.5g of sugar is needed to make 5 cakes. How much sugar is needed for 8 cakes?
    13·2 answers
  • Write an equation for the proportional relationship shown in the table.
    13·1 answer
  • I need help with 5 and 6. May anyone turn them into words? ILL GIVE BRAINLIEST FOR 2 RESPONSES
    10·1 answer
  • In ΔNOP, \overline{NP}
    11·2 answers
  • 15/3x-22/4x-29/5y+2/2Y
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!