Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
9514 1404 393
Answer:
birr 80
Step-by-step explanation:
The total number of ratio units is 1+3+5+7 = 16. The largest amount is represented by 7 ratio units, so is 7/16 of the total. The total contributed is ...
16/7 × (birr 35) = birr 80
Answer:
4.5454 seconds
Step-by-step explanation:
1.5 km is equal to 1,500 m
1,500 m divided by 330.0 m/s = 4.5454 s
The answer is D= undefined :)
