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il63 [147K]
3 years ago
13

Show work

Mathematics
1 answer:
dexar [7]3 years ago
7 0

Answer:

b.

Step-by-step explanation:

(5x^5 + 4) - (2x^3+9)+(6x^5-x^3)

5x^5 + 4 - 2x^3 - 9 + 6x^5 - x^3

5x^5 + 6x^5 = 11x^5

-2x^3 - x^3 = -3x^3

+4 -9 = -5

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Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle
mario62 [17]

Step-by-step explanation:

The distance formula between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points.

A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

\sqrt5

used (\sqrt{a})^2=a for a ≥ 0.

AB^2+BC^2=AC^2 therefore ΔABC is a right triangle.

6 0
3 years ago
Use the model to write the equivalent fraction. The colored pieces show parts of the whole.
BabaBlast [244]

What is your question?

4 0
3 years ago
4y-7x=16 solve for y
kompoz [17]
I think the answer would be  x= 4/7 y = +-16/7
4 0
3 years ago
Read 2 more answers
A kite has a height of 36 inches and a width of 30 inches. Explain how to use the area formula for a triangle to find the area o
mote1985 [20]

Height of the kite is = 36 inches.

Width of the kite is = 30 inches

One of the ways to find the area is to draw a vertical line to break the kite into two equal triangles. Mark the base as 36 inches and height as 15 inches .

Now we will use the formula area=\frac{1}{2}*base*height to find the area of each triangle. Then we will add both the areas to find the area of the kite.

Area of 1 triangle = \frac{1}{2}*36*15 = 270 square inches

Area of the 2nd triangle is also = 270 square inches

Hence, area of the kite = 270+270 = 540 square inches

8 0
3 years ago
Read 2 more answers
Substitution for:<br> X-5y=10<br> 2x-10y=20
sergey [27]
Since you need an isolated variable to use the substitution method, we need to re-arrange one of the equations. This will probably be easiest to do with the first one.
Add 5y to both sides of the first equation.
x=10+5y
Now, in the second equation, put in 10+5y in any spot that has an x.
2(10+5y)-10y=20
Distribute the 2 to both numbers in the parenthesis.
20+10y-10y=20
Combine like terms.
20=20
This means that the two equations are actually the same. You can see this if you multiply the whole first equation by 2
2(x-5y=10)
2x-10y=20, which is the same as the second equation. Therefore, the two equations are actually the same one.
5 0
3 years ago
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