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bixtya [17]
2 years ago
15

Which is the correct solution of the system of linear equations?

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
8 0
Number one is the correct one i think
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Please help me ! I don’t know !
goblinko [34]

Answer:

5

Step-by-step explanation:

this will endure the bitextular number course and follow the index pattern once you do that follow the question to get 5

7 0
3 years ago
Read 2 more answers
D = {x|x is a whole number}
pickupchik [31]

The given statement is true.

Step-by-step explanation:

Given sets are:

D = {x|x is a whole number}

E = {x|x is a perfect square between 1 and 9}

F = {x|x is an even number greater than or equal to 2 and less than 9}

as the sets are given in set builder notation,, we will first write the sets in set notation.

So,

D = {0,1,2,3,4,...}

E = {4,9}

F = {2,4,6,8}

Now,

EUF = {4,9} U {2,4,6,8}

= {2,4,6,8}

Hence,

The given statement is true.

Keywords: Union,sets

Learn more about sets at:

  • brainly.com/question/9381523
  • brainly.com/question/9231234

#LearnwithBrainly

4 0
3 years ago
What is the difference between a question asking you to factor a quadratic equation completely and a question asking you to solv
saveliy_v [14]
Both mean to factor, I've never heard of a difference
5 0
3 years ago
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In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and
Romashka [77]
<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>

7 0
3 years ago
April shoots an arrow upward at a speed of 80 feet per second from a platform 25 feet high. The pathway of the
zaharov [31]

Answer:

The maximum height of the arrow is 125 feet.

Step-by-step explanation:

The pathway of the arrow can be represented by the equation,

h = -16t^2 +80t + 25 .....(1)

Where h is height in in feet and t is time in seconds.

It is required to find the maximum height of the arrow. For maximum height, \dfrac{dh}{dt}=0.

So,

\dfrac{d(-16t^2 +80t + 25)}{dt}=0\\\\-32t+80=0\\\\t=\dfrac{80}{32}\\\\t=2.5\ s

Put t = 2.5 s in equation (1). So,

h = -16(2.5)^2 +80(2.5) + 25\\\\h=125\ \text{feet}

So, the maximum height of the arrow is 125 feet.

6 0
3 years ago
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