Answer:
59.16 units
Step-by-step explanation:
Given that,
The length of rectangle, L = 13
The breadth of the rectangle, B = 6
The perimeter of the shaded region = perimeter of rectangle - 2(perimeter of semicircle)
![P=13\times 6-[2\times \dfrac{2\pi r}{2}]\\\\=78-2\pi r\\\\=78-2\times 3.14\times 3\\\\=59.16](https://tex.z-dn.net/?f=P%3D13%5Ctimes%206-%5B2%5Ctimes%20%5Cdfrac%7B2%5Cpi%20r%7D%7B2%7D%5D%5C%5C%5C%5C%3D78-2%5Cpi%20r%5C%5C%5C%5C%3D78-2%5Ctimes%203.14%5Ctimes%203%5C%5C%5C%5C%3D59.16)
So, the perimeter of the shaded region is 59.16 units.
Answer:
There is no answer
My Logic:
The picture does not specify the degree of angle for each corner, nor can i understand what the random "a" is. also the side all the way to the left has an un-readable number.
I have done this question yesterday it is 1 and 3
CommentI think you need brackets to clarify what you mean. I think it should be written as
10b/(2b + 8)
If that is the case the reciprocal is
(2b + 8)/10b You just turn everything up side down. There are technical ways of doing this, but the easiest way is just to do what I just did.
Put the numerator in the denominator,
Put the denominator in the numerator.
You could simplify this a bit.
2b/10b + 8/10b
which reduces further.
1/5 + 4/5b
Just to make sure you understand where that b is, I will do this in
Latex.
Alternate answerIf you do mean what your wrote then the reciprocal is 2b / 10b + 8 which is 1/5 + 8 = 8 + 0.2 = 8.2
The 8 has nothing to do with the reciprocal under these conditions.
The answerI have given you all the choices I can think of without going into decimals. If you have choices, please list them under the comments.
There is no graph appearing. :( sorry
