In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be
5120 N - 4050 N = 1070 N
(it's positive, so the net vertical force is pointing upward)
In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be
950 N - 1520 N = -570 N
(negative means the net horizontal force points to the left)
So the net force on the balloon is the vector
<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>
(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)
The magnitude of the net force on the balloon is the magnitude of this vector:
<em>F</em> = √((1070 N)² + (-570 N)²)
<em>F</em> ≈ 1212 N
Answer:
600Joules
Explanation:
The energy stored by this battery is calculated using the energy formula;
E = Q× v
Where E is energy
Q is the charge
v is voltage
Hence E = 50 × 12 = 600Joules
Note Q = 12 ampere minute
Okay. I'm willing to do that. But first you'll have to tell me something about the sample in question 3.
Answer:
Friction opposes motion.
Explanation:
If there is relative motion, the frictional force is the kinetic force of friction.
