A 3.0-kilogram object is acted upon by an impulse having a magnitude of 15 newton•seconds. What is the magnitude of the object’s
1 answer:
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Answer:
For vector u, x component = 10.558 and y component =12.808
unit vector = 0.636 i+ 0.7716 j
For vector v, x component = 23.6316 and y component = -6.464
unit vector = 0.9645 i-0.2638 j
Explanation:
Let the vector u has magnitude 16.6
u makes an angle of 50.5° from x axis
So
Vertical component
So vector u will be u = 10.558 i+12.808 j
Unit vector
Now in second case let vector v has a magnitude of 24.5
Making an angle with -15.3° from x axis
So horizontal component
Vertical component
So vector v will be 23.6316 i - 6.464 j
Unit vector of v