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Aleksandr [31]
3 years ago
13

A 3.0-kilogram object is acted upon by an impulse having a magnitude of 15 newton•seconds. What is the magnitude of the object’s

change in momentum due to this impulse?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0
The mass of the object doesn't matter. The change in its momentum is equal to the impulse that changed it ... 15 N-sec.
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dalvyx [7]
A. Add it's Kinetic and Potential energies
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A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between
mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

Electric field strength E = 155 N/C

Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

Substitute E and d into the above formula

155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

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3 years ago
13. If both the directions of velocity and acceleration are negative, ...........
lawyer [7]

Answer:

B)velocity of object decreases

Explanation:

Consider the positive x axis as positive direction

Assume a body moving in negative x-axis direction

It's acceleration also alone negative x-axis direction

So according to our consideration

velocity and acceleration values are negative

That is both are towards negative x direction

But as both velocity and acceleration are in same direction, MAGNITUDE of velocity increases

But as magnitude increases in negative direction, velocity value decreases

But speed value increases(As speed is scalar and velocity is a vector)

3 0
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On a velocity time graph, the slope tells you the ______ of the object.
Paraphin [41]
The acceleration is the correct answer
7 0
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A drone is flying horizontally when it runs out of battery and begins to free fall from 20m. No drag. If it lands 60m away (in t
rewona [7]

Answer:

Explanation:

Remark

At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.

Givens

h = 20 m

hd = 60 m

g = 9.81

vi = 0

Formula

d = vi*t + 1/2 a * t^2                  We are solving for t

Solution

When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters

d = 0*t + 1/2 * 9.81 a* t^2

20 = 4.91 * t^2                          Divide by 4.91

20/4.91 = 4.91 t^2 / 4.91    

4.073 = t^2                              Take the square root of both sides.

t = 2.02 seconds

Horizontal

d = 60 m

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v = ?

Note: there is no horizontal deceleration or acceleration

v = d/t

v = 60/2.02

Answer: v = 29.73 m/s

3 0
2 years ago
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