1 m = 100 cm
1 m^3 = 1^6 cm^3
so 1 cm^3 = 10^-6 m^3
and 1 L = 1000 cm^3 = 10^-3 m^3
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
Answer:
18
Step-by-step explanation:
(7+2)2
First, Remeber always do what is in parentheses.
So (7+2) = 9
then you multiply 9 by 2 which gives you 18.
Divide 3 and 15 by three and get 1/3