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Lilit [14]
4 years ago
8

Two chemical reactions are shown. Which statements is true?

Chemistry
1 answer:
Marizza181 [45]4 years ago
7 0

Answer:

The answer is b

Explanation:

they both are decomposition

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Using the periodic table to locate each element, write the electron configuration of(c) Re.
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Rhenium is a chemical element with the symbol Re and atomic number 75. The electron configuration of Re is [Xe] 6s^{2} 4f^{14} 5d^{5}.

<h3>How to write an electronic configuration?</h3>

1. Identify the given element and its atomic number from the periodic table.

2. Write the electron configuration by the energy level and the type of orbital first, then the number of electrons present in the orbital as superscript.

The easiest way to write the electronic configuration for any element is by   using a diagonal rule for electron filling order in the different subshells according to the Aufbau principle.

The 3 rules for writing the electron configuration in the orbital box diagram are – the Aufbau rule, the Pauli-exclusion rule, and Hund's Rule.

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2 years ago
Which conclusion could be made from Ernest Rutherford’s gold foil experiment?
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The nucleus while large has a small ratio of mass when dealing with atoms, they are very spread out and are mostly solid with a blocky shape.
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4 years ago
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Select true or false: if the ph of pure water is 7.0, the hydroxide ion concentration in pure water is 1 × 10–7 m.
Vedmedyk [2.9K]

Answer:

True

Explanation:

as the ph of pure water is 7

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A blood test shows clumps only in wells containing anti-A and anti-B antibodies. The Rhesus test was negative. Which is the corr
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I believe AB- unless I’m reading the question wrong.
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HELP PLEASEEE <br>it's for an exam on monday​
zhannawk [14.2K]

From the stoichiometry of the reaction, we can see that the volume of carbon monoxide reacted is 44.8 L.

<h3>What is stoichiometry?</h3>

Stoichiometry is used to obtain the amount of substance reacted or the amount of product formed.

Number of moles of CO2 in 88g = 88g/4 g/mol = 2 moles

Molar mass of carbon monoxide = 12 + 16 = 28g/mol

We can see that 1 mole of oxygen was used in the reaction hence the mass of oxygen used is 32 g/mol. Given the stoichiometry of the reaction, 28g of carbon monoxide was burned.

If 1 mole of a gas occupies 22.4 L

2 moles of a gas occupies 2 moles  * 22.4 L/1 mole

= 44.8 L

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4 0
3 years ago
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