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diamong [38]
3 years ago
6

The main reason that cs2 has a higher boiling point than co2 is that cs2

Chemistry
1 answer:
OlgaM077 [116]3 years ago
4 0

Explanation:

Inspite of having similar intermolecular forces, CS2 has a higher boiling point than CO2, since it has a greater molar mass. The potential energy of molecules reduces until a certain level as they get closer to each other. Although the polarity of both CO2 and CS2 are cancelled because of their linear structure.

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Describe how iron and sulfur can be an element, mixture, and a compound.
Vlad1618 [11]

iron is a metal and sulfur is a non-metal and both are in the periodic table which means they are elements. Together they can form a compound with an ionic bond. and can be mixed to form a mixture.

8 0
4 years ago
Compute the equilibrium constant at 25 ∘C for the reaction between Sn2+(aq) and Cd(s), which form Sn(s) and Cd2+(aq). Express yo
Radda [10]

Answer:

6.1×10^8

Explanation:

The reaction is;

Sn^2+(aq) + Cd(s) -----> Sn(s) + Cd^2+(aq)

E°cell = E°cathode - E°anode

E°cathode= -0.14 V

E°anode= -0.40 V

E°cell = -0.14-(-0.40)

E°cell= -0.14+0.40

E°cell= 0.26 V

But

E°cell= 0.0592/n log K

E°cell= 0.0592/2 log K

0.26= 0.0296log K

log K = 0.26/0.0296

log K= 8.7838

K= Antilog (8.7838)

K= 6.1×10^8

8 0
3 years ago
Is blood acid base or neutral
katen-ka-za [31]
It is usually neutral becase its is close to neutral number 7
5 0
4 years ago
Read 2 more answers
A BaSO4 slurry is ingested before the gastrointestinal tract is x-rayed because it is opaque to x-rays and defines the contours
NNADVOKAT [17]

Explanation:

The given reaction equation is as follows.

         BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO_{4}^{2-}(aq)

The value of \Delta G^{o} = 59.1 kJ/mol

We know that ,

            \Delta G^{o} = -RT ln K_{sp}

 or,       ln K_{sp} = -(\frac{\Delta G^{o}}{RT})


                       = -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]  

            = -22.93

or,      K_{sp} = e^{-22.93}

                      = 1.1 \times 10^{-10}

      K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]

Therefore,      [Ba^{2+}] =\sqrt{K_{sp}}

                                        = \sqrt{ 1.1 \times 10^{-10}}

                                         = 1.05 \times 10^{-5} M

Therefore, we can conclude that the value of [Ba^{2+}] in the intestinal tract is 1.05 \times 10^{-5} M.

7 0
3 years ago
What is an evenly distributed, uniform mixture called?
ryzh [129]

Answer:

An evenly distributed, uniform mixture is called a homogeneous mixture.

Explanation:

4 0
3 years ago
Read 2 more answers
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