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3 years ago

What happened to the boiling point of water after mixing it with table salt??

Chemistry

2 answers:

GaryK [48]3 years ago

6 0

Answer:

Boiling point of water increases wben salt is added to the water this propertiy is known as elevation of boiling points

Explanation:

otez555 [7]3 years ago

3 0

Answer:When table salt is added to water the resulting solution has a higher boiling point than the water did by itself. The ions form an attraction with the solvent particles that then prevent the water molecules from going into the gas phase. Therefore, the salt-water solution will not boil at 100oC.Jun

Explanation:

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Based on the equation, how many grams of Br2 are required to react completely with 42.3 grams of AlCl3? AlCl3 + Br2 → AlBr3 + Cl

rusak2 [61]

Answer:

76.1 grams.

Explanation:

From the balanced reaction:

2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,

2.0 moles of AlCl₃ reacts with 3.0 moles of Br₂ to produce 2.0 moles of AlBr₃ and 3.0 moles of Cl₂.

We need to calculate the no. of moles of (42.3 g) of AlCl₃:

no. of moles of AlCl₃ = mass/molar mass = (42.3 g)/(133.34 g/mol) = 0.3172 mol.

Using cross multiplication:

2.0 moles of AlCl₃ react completely with → 3.0 moles of Br₂.

0.3172 mol of AlCl₃ react completely with → ??? moles of Br₂.

∴ The no. of moles of Br₂ = (0.3172 mol)(3.0 mol)/(2.0 mol) = 0.4759 mol.

∴ The amount of grams of Br₂ are required to react completely with 42.3 grams of AlCl₃ = (no. of moles of Br₂)(molar mass) = (0.4759 mol)(159.81 g/mol) = 76.05 g ≅ 76.1 g.

4 0

3 years ago

What is the limiting reactant and theoretical yield if 0.483 mol of Ti and 0.911 mol Clare used in this reaction: Ti + 2Cl2 → Ti

Mariana [72]

Answer : The limiting reactant is $Cl_2$ and the theoretical yield will be 86.45 grams.

Explanation : Given,

Moles of $Ti$ = 0.483 mole

Moles of $Cl_2$ = 0.911 mole

Molar mass of $TiCl_4$ = 190 g/mole

First we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is,

$Ti+2Cl_2\rightarrow TiCl_4$

From the balanced reaction we conclude that

As, 2 moles of $Cl_2$ react with 1 mole of $Ti$

So, 0.911 moles of $Cl_2$ react with $\frac{0.911}{2}=0.455$ moles of $Ti$

From this we conclude that, $Ti$ is an excess reagent because the given moles are greater than the required moles and $Cl_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $TiCl_4$ .

As, 2 moles of $Cl_2$ react to give 1 moles of $TiCl_4$

So, 0.911 moles of $Cl_2$ react to give $\frac{0.911}{2}=0.455$ moles of $TiCl_4$

Now we have to calculate the mass of $TiCl_4$ .

$\text{Mass of }TiCl_4=\text{Moles of }TiCl_4\times \text{Molar mass of }TiCl_4$

$\text{Mass of }TiCl_4=(0.455mole)\times (190g/mole)=86.45g$

Therefore, the theoretical yield will be 86.45 grams.

4 0

3 years ago

When iron metal reacts with sulfuric acid, it produces iron (III) sulfate and hydrogen gas. Balance the equation: Fe + H2SO4 → F

gavmur [86]

<h3>Answer:</h3>

Balanced Equation; 2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂
Why balance?: To obey the law of conservation of mass
Subscripts can not be changed, since they show the actual number of atoms of each element in a compound.

<h3>Explanation:</h3>

The balanced equation for the reaction between the iron metal and sulfuric acid to produces iron (III) sulfate and hydrogen gas is given by;

2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂

Balancing chemical equations ensures that they obey the law of conservation of mass which requires the mass of reactants and the mass of products to be equal.
Balancing is done by putting coefficients on reactants and products while not affecting the subscripts as subscripts show the actual number of atoms of an element in a compound.

6 0

3 years ago

1. How does adding energy to a solid affect the motion of the particles? 2. How can a gas at room temperature (like oxygen) beco

Oksanka [162]

I am not sure sorry

6 0

4 years ago

3.0 g aluminum and 6.0 g of bromine react to form AlBr3 2Al+3Br2=2AlBr3 How much product would be produced? How much reagent wou

juin [17]

2Al + 3Br2 -------------> 2AlBr3

3 g Al = 0.11 mol Al.

6 g Br2 = 0.0375 mole bromine (it is diatomic). 

moles of aluminium will take part in reaction = 0.0375 X (2/3) = 0.025. 

Gram-mole of AlBr3 will be produced = 0.025 mole = 6.6682 g.
moles of Al left = 0.11 - 0.025 = 0.086

8 0

3 years ago

What happened to the boiling point of water after mixing it with table salt??​

What happened to the boiling point of water after mixing it with table salt??