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Korolek [52]
2 years ago
9

Can someone pls help me!!! NO LINKS... I will mark brainiest to.

Mathematics
2 answers:
Vadim26 [7]2 years ago
7 0

Answer:

c it the answer

Step-by-step explanation:

Alla [95]2 years ago
7 0
I don’t really sure, but I thinks that is D
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In the parallelogram shown in the picture solve for Z
deff fn [24]

In a parallelogram, opposite angles are congruent.

Since angles z and 124° are opposite angles in the parallelogram, they are congruent angles.

Therefore we have:

z=124°

5 0
9 months ago
Which of the following is the equation of a line that passes through the points (1,6) and (2,1)
anastassius [24]

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

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To calculate m use the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (1, 6) and (x₂, y₂ ) = (2, 1)

m = \frac{1-6}{2-1} = - 5, hence

y = - 5x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

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5 0
2 years ago
Read 2 more answers
Equation practice with angle addition
Triss [41]

Answer:

36 degrees

Step-by-step explanation:

since, m<AOB is a right angle, we shall just create an equation:

M<AOB+M<BOC=90 degrees

Substitute: 6z-12+3z+30=90

Solve: 6z+3x=9z

-12+30=18

so, 9z+18=90 degrees

           -18  -18

9z=72

z=8

So if z=8, then we should fit it so that it matches measure of AOB.

6z-12

6 times 8=48

48-12= 36

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The point (8,-4) lies on a circle. What is the length of the radius of this circle if the center is located at (5,-7)
Kamila [148]
Notice the picture, the radius is just the distance from the
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\bf \textit{distance between 2 points}\\ \quad \\\\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{5}}\quad ,&{{ -7}})\quad &#10;%  (c,d)&#10;&({{ 8}}\quad ,&{{ -4}})&#10;\end{array}\qquad &#10;%  distance value&#10;\\\\\\&#10;\begin{array}{llll}&#10;d = &\sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\&#10;&\qquad \uparrow \\&#10;&radius&#10;\end{array}

\bf \begin{array}{llll}&#10;d = &\sqrt{({{ 8}}-{{ 5}})^2 + ({{ -4}}-{{(-7)}})^2}\\&#10;&\qquad \uparrow \\&#10;&radius&#10;\end{array}&#10;\\\\\\&#10;d=\sqrt{(3)^2+(-4+7)^2}\implies d=\sqrt{3^2+3^2}\implies d=\sqrt{18}&#10;\\\\\\&#10;d=\sqrt{9\cdot 2}\implies d=\sqrt{3^2\cdot 2}\implies d=3\sqrt{2}



4 0
3 years ago
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