Answer:
The relationship is not a function
Step-by-step explanation:
Solve for the x-max or h :\
plug it in to equation to get k:/
-8+16+3=11=k
solve for a by pluging (0,0)
then a= -11/4
Answer:
I am stuck at 2m^2 + 6m- 32 as finding the roots of the quadratic equation is unproductive
Answer:
a) 96m
b) 2 m/s^2
Step-by-step explanation:
The distance travelled in a velocity time graph as shown in the image is the area of the shape. As such, considering the first 14 seconds, the distance covered will be computed by finding the area of the shape.
Note that the shape to be considered ends t the 14 seconds mark. This shape is a trapezium. The area of a trapezium is given as
A = 1/2(a + b) h
where a and b are the parallel sides of the trapezium and h is the height As such, the distance covered in the first 14 seconds
= 1/2 (14 + 10) * 8
= 4 * 24
= 96m
The acceleration after 4 seconds
Acceleration is the rate of change of velocity with time, at time 0 second, the velocity is also 0 but at time 4 seconds, the velocity is 8 m/s hence, the acceleration after 4 seconds
= 8/4
= 2 m/s^2
Answer:
26
Step-by-step explanation:
2+4(2+4)
=2+(4)(6)
=2+24
=26
