The number<span> is between integers, so it can't be an integer or a whole </span>number<span>. It's written as a ratio of two integers, so it's a </span>rational number<span> and not irrational. All</span>rational numbers<span> are real </span>numbers<span>, so this </span>number<span> is </span>rational<span> and real.</span>
Answer:
1) 22.5 A
2) 112 B
3) 430 L
4) 576 P
5) 486 L
6) 624 S
Code is A B L P L S
Step-by-step explanation:
1) Area of a triangle = 1/2 * base * height = 1/2 *5*9 = 22.5
2) Area of a parallelogram = base x height = 14 x 8 = 112
3) Area of a rectangular prism = 2(length * width) + 2*(length + height) + 2 *(length *height)
= 2(15x7 + 15*5 + 7*5)
= 2(105 + 75 + 35)
= 2 * 215
= 430
4) Volume of a triangular prism = 1/2 * base * length * height
= 1/2 * 8 * 16 * 9
= 576
5) A cube has six surfaces. Each surface has an area of s x s where s is the length of each side. In this case, each side has area of 9x9 = 81. Total surface area = 6 x 81 = 486 and that is the paper required
6) The trailer is a rectangular prism so its volume = length x width x height = 13 6 x 8 = 624
Now you have to look at each value and see which letter it corresponds to. For example answer 1) is 22.5 which lies between 0-100 so it gets letter A, answer (2) is 112 which lies in the range 101-200 so it gets the letter B and so on
Answer:
is isosceles.
Step-by-step explanation:
Please have a look at the attached figure.
We are <u>given</u> the following things:


Let us try to find out
and
. After that we will compare them.
<u>Finding </u>
<u>:</u>
Side EG is a straight line so 
is sum of internal
and external 
<u>Finding </u>
<u>:</u>
<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.
i.e. external
= 

Comparing equations (1) and (2):
It can be clearly seen that:

The two angles of
are equal hence
is isosceles.
Simple, finding markdown, use these two formulas.
Markdown=Original-New
and
Percent Markdown= Markdown Amount/Original*100
So,
Markdown=612-450
M=162
Markdown%= 162/612*100
M%=0.2647*100
M%=26.5 (rounded)
Thus, there was a 26.5% decrease.