Ask question

Ask question

All categories

3 years ago

11

suppose you push down on the handle of a bicycle pump with a force of 20N .the handle moves 0.3m and there is no heat between th

e pump and its surroundings what is the change in thermal energy of the bicycle pump?

1 answer:

elena-s [515]3 years ago

6 0

Answer:

6 Joules

Explanation:

The change in internal energy must be equal the work done by pushing the handle with a 20 N force a distance of 0.3 meters. That is:

Change in internal energy = Work = 20 * 0.3 J = 6 Joules

You might be interested in

Acartravelingat15m/sstartstodeceleratesteadily.Itcomestoacompletestopin10seconds.Whatisit'sacceleration? a. 1500 m/s b. -1.5 m/s

Amiraneli [1.4K]

Answer:

b. -1.5 m/s²

Explanation:

Given the following data;

Initial velocity = 15m/s

Time = 10 seconds.

Since the car came to rest, final velocity = 0m/s

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{initial \; speed - final \; speed}{time}$

$a = \frac{v - u}{t}$

Where,

a is acceleration measured in $ms^{-2}$

v and u is initial and final speed respectively, measured in $ms^{-1}$

t is time measured in seconds.

Substituting into the equation, we have;

$Acceleration, a = \frac{0 - 15}{10}$

$Acceleration, a = \frac{-15}{10}$

Acceleration = -1.5 m/s²

6 0

3 years ago

What would the acceleration of a car be from a stoplight if it started at 0 m/s and reached a

trapecia [35]

Answer:

The acceleration of a car would be: $a=12.8$ m/s²

Explanation:

Given

Initial velocity = $v_1=0$ m/s

Final velocity = $v_f=100$ m/s

Time elapsed = $t = 7.8$ s

To determine

We need to determine the acceleration of a car.

We know that acceleration is basically the rate of change in velocity over time.

Thus,

We can determine the acceleration using the formula

$\:\:\:a=\:\frac{v_f-v_i}{t}$

where

$a$ is the acceleration

$v_1$ is the initial velocity

$v_f$ is the final velocity

$t$ is time elapsed

now substituting the values $v_1=0$ , $v_f=100$ , and $t = 7.8$ in the formula

$\:\:\:a=\:\frac{v_f-v_i}{t}$

$a=\:\frac{100-0}{7.8}$

$a=\frac{100}{7.8}$

$a=12.8$ m/s²

Therefore, the acceleration of a car would be: $a=12.8$ m/s²

3 0

3 years ago

Advantage of using infared camera

vladimir2022 [97]

it can be used to detect

3 0

3 years ago

Read 2 more answers

A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio

Blababa [14]

Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

$mg sin \theta - \mu N = ma$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity, $\theta=39^{\circ}$ being the angle of the incline

$\mu N$ is the frictional force, with $\mu = 0.6$ being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

$N-mg cos \theta =0$

where $mg cos \theta$ is the component of the weight in the direction perpendicular to the slope. Solving for N,

$N=mg cos \theta$

Substituting into (1), solving for a, we find the acceleration:

$a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2$

6 0

4 years ago

A 1.5 kg ball pushed with a force of 13.5 N accelerates to the left. What is the acceleration of the ball?

GarryVolchara [31]

Explanation:

F= ma

13.5 =1.5a

1.5a/1.5 =13.5/1.5

a= 9 m/s^2

4 0

3 years ago