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2 years ago

How does the law of conservation apply to Earth's Energy Budget?

Physics

1 answer:

Molodets [167]2 years ago

4 0

Answer:

The balance between incoming energy from the sun and outgoing energy from Earth ultimately drives our climate. This energy balance is governed by the first law of thermodynamics, also known as the law of conservation of energy.

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Where are protons and neutrons found in an atom

mr Goodwill [35]

Answer:

The Nucleus

Explanation:

Protons and Neutrons are found in the nucleus of an atom.

3 0

3 years ago

Read 2 more answers

In the absence of air resistance, at what other angle will a thrown ball go the same distance as one thrown at an angle of 75 de

snow_tiger [21]

As we know that range of the projectile motion is given by

$R = \frac{v^2 sin(2\theta)}{g}$

here we know that range will be same for two different angles

so here we can say the two angle must be complementary angles

so the two angles must be

$\theta, 90 - \theta$

so it is given that one of the projection angle is 75 degree

so other angle for same range must be 90 - 75 = 15 degree

so other projection angle must be 15 degree

5 0

3 years ago

Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all. Joffre

lana [24]

Answer:

R.E.T.A.R.D.A.T.I.O.N

Explanation:

It won't let me spell it normal

7 0

3 years ago

A cannon can make a maximum angle of 30 degrees with the horizon. What is the minimum speed of a cannon ball if it must clear a

stiks02 [169]

Answer:

28.3 m/s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Maximum height (H) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

Thus, we can obtain the minimum velocity cannon ball by using the following formula:

H = u²Sine² θ / 2g

10 = u² × (Sine 30)² / 2× 10

10 = u² × (0.5)² / 20

10 = u² × 0.25 / 20

10 = u² × 0.0125

Divide both side by 0.0125

u² = 10/ 0.0125

u² = 800

Take the square root of both side

u = √800

u = 28.3 m/s

Therefore, the minimum speed of the cannon ball is 28.3 m/s

8 0

2 years ago

What are the horizontal and vertical velocities of a stunt bike that leaves a ramp at 100 km/hr and at an angle of 35 degrees?

Alex787 [66]

Horizontal velocity: 81.9 km/h

Vertical velocity: 57.4 km/h

Explanation:

We can solve this problem by resolving the velocity vector into its component along the horizontal and vertical direction.

The horizontal velocity of the stunt bike is given by:

$v_x = v cos \theta$

where

v = 100 km/h is the magnitude of the velocity

$\theta=35^{\circ}$ is the angle of projection

Substituting, we find

$v_x = (100)(cos 35^{\circ})=81.9 km/h$

The vertical velocity instead is given by

$v_y = v sin \theta$

where

$v=100 km/h$

$\theta=35^{\circ}$

Substituting,

$v_y = (100)(sin 35^{\circ})=57.4 km/h$

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

4 0

3 years ago