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3 years ago

Wholl do absolutley anything to get a really hard question answered whos a girl

Physics

2 answers:

Lemur [1.5K]3 years ago

7 0

Answer:

meeee

Explanation:

Charra [1.4K]3 years ago

4 0

Answer:

Explanation:

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Two coils that are separated by a distance equal to their radius and that carry equal currents such that their axial fields add

jok3333 [9.3K]

Answer:

When x = 2.8 cm, $B_{x1} = 0.0265 T$

When x = 5.5 cm, $B_{x2} = 0.0209 T$

when x = 7.3 cm, $B_{x3} = 0.0169 T$

When x = 11.0 cm, $B_{x4} = 0.0103 T$

Explanation:

According to Biot-Savart law,

$B_{x} = \frac{N \mu_{o}IR^{2} }{2(x^{2} +R^{2} )^{3/2} }\\$ .......................(1)

R = 11.0 cm = 0.11 m

I = 17.0 A

N = 300 turns

$\mu_{o} = 4\pi * 10^{-7} N/A^{2}$

When x₁ = 2.8 cm = 0.028 m

$B_{x1} = \frac{300 *(4\pi * 10^{-7} ) * 17 *0.11^{2} }{2(0.028^{2} +0.11^{2} )^{3/2} }\\B_{x1} = 0.0265 T$

When x₂ = 5.5cm = 0.055 m

$B_{x2} = \frac{300 *(4\pi * 10^{-7} ) * 17 *0.11^{2} }{2(0.055^{2} +0.11^{2} )^{3/2} }\\B_{x2} = 0.0209 T$

When x₃ = 7.3 cm = 0.073 m

$B_{x3} = \frac{300 *(4\pi * 10^{-7} ) * 17 *0.11^{2} }{2(0.073^{2} +0.11^{2} )^{3/2} }\\B_{x3} = 0.0169 T$

When X₄ = 11.0 cm = 0.11 m

$B_{x4} = \frac{300 *(4\pi * 10^{-7} ) * 17 *0.11^{2} }{2(0.11^{2} +0.11^{2} )^{3/2} }\\B_{x4} = 0.0103 T$

4 0

4 years ago

002 10.0 points note: report your answer in joules here. a proton and an antiproton, both at rest with respect to one another, m

Ulleksa [173]

The mass of the proton is:
$m_p = 1.67 \cdot 10^{-27} kg$
and the mass of the antiproton is exactly the same, so the total mass of the two particles is $2m_p$ .

In the annihilation, all the mass of the two particles is converted into energy, and the amount of this energy is given by Einstein's equivalence between mass and energy:
$E=Mc^2$
where M is the mass converted into energy and c is the speed of light. In this example, $M=2m_p$ , therefore the energy released is
$E=2m_p c^2 = 2 (1.67 \cdot 10^{-27} kg)(3\cdot 10^8 m/s)^2=3 \cdot 10^{-10}J$

3 0

3 years ago

Is the Florida scrub a forest or grassland

PIT_PIT [208]

It is a forest. Hope this helps. Much luck

4 0

3 years ago

A tuning fork is held over a resonance tube, and resonance occurs when the surface of the water is 12 cm below the top of the tu

Rainbow [258]

Answer:

786 Hz

Explanation:

Recall, the speed of sound is

v = 332 + 0.6t

Where t = 23°

v = 332 + 0.6(23)

v = 332 + 13.8

v = 345.8 m

Also, it is known that distance between two consecutive resonance length is half of the wavelength.

L2 - L1 = λ/2

34 - 12 = λ/2

λ/2 = 22

λ = 44 cm

Finally, remember that also

Frequency = speed/ wavelength

Frequency = 345.8/0.4

Frequency = 786 Hz

Therefore, the frequency of the tuning fork is 786 Hz

6 0

3 years ago

The mass of an object is 5 kg .what does it mean

aivan3 [116]

Answer:

Explanation:

If the mass of an object is 5 kg, it means that it weighs 5 kg

Hope this helps

plz mark as brainliest!!!

4 0

3 years ago