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Neporo4naja [7]
3 years ago
15

Halfway through Mila's run, when the music stopped playing, was there energy in Mila's phone? What is your

Physics
2 answers:
Andrej [43]3 years ago
8 0

Answer:

No energy

Explanation:

Artyom0805 [142]3 years ago
6 0
There was no energy
You might be interested in
BEST ANSWER GETS BRAINLIEST!
wel

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

8 0
3 years ago
A moving particle is subject to conservative forces only. When its kinetic energy decreases by 10 J, what happens to its mechani
satela [25.4K]

Answer:

Its mechanical energy is the same.

Explanation:

If forces are only conservative, the mechanical energy will be the same.

It can be different if energy get transformed in another kind of energy like elastic energy for example, although the amount of energy is always the same.

If we just have mechanical energy not geting transformed we have:

Em=K+U

Em: Mechanical energy

K: Kinetic energý

U: Potential energy

Then if Kinetic energy decreases 10J, Potential energy will grow up 10J to keep the same amount of mechanical energy.

8 0
3 years ago
The Ha line of the Balmer series is emitted in the transition from n-3 to n 2. Compute the wavelength of this line for H and 2H.
Citrus2011 [14]

Explanation:

According to Rydberg's formula, the wavelength of the balmer series is given by:

\frac{1}{\lambda}=R(\frac{1}{2^2}-\frac{1}{3^2})

R is Rydberg constant for an especific hydrogen-like atom, we may calculate R for hydrogen and deuterium atoms from:

R=\frac{R_{\infty}}{(1+\frac{m_e}{M})}

Here, R_{\infty} is the "general" Rydberg constant, m_e is electron's mass and M is the mass of the atom nucleus

For hydrogen, we have, M=1.67*10^{-27}kg:

R_H=\frac{1.09737*10^7m^{-1}}{(1+\frac{9.11*10^{-31}kg}{1.67*10^{-27}kg})}\\R_H=1.09677*10^7m^{-1}

Now, we calculate the wavelength for hydrogen:

\frac{1}{\lambda}=R_H(\frac{1}{2^2}-\frac{1}{3^2})\\\lambda=[R_H(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=[1.0967*10^7m^{-1}(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=6.5646*10^{-7}m=656.46nm

For deuterium, we have M=2(1.67*10^{-27}kg):

R_D=\frac{1.09737*10^7m^{-1}}{(1+\frac{9.11*10^{-31}kg}{2*1.67*10^{-27}kg})}\\R_D=1.09707*10^7m^{-1}\\\\\lambda=[R_D(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=[1.09707*10^7m^{-1}(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=6.5629*10^{-7}=656.29nm

5 0
3 years ago
Mechanical energy is a term that can be used to describe
Citrus2011 [14]

A, both potential and kinetic energy as mechanical energy is the sum of potential and kinetic energy.

5 0
3 years ago
Read 2 more answers
The figure shows an object moving from point B to point A and the gravitational potential energy of the object-Earth system at d
Natasha2012 [34]

The amount of kinetic energy that will be gained from the particle as it moves from point B to point A is 12U₀.

Since the particle moves through in a projectile path (trajectory). The gravitational potential energy acts on the particle in the downward direction.

A resistive force refers to a force that resists and acts in the direction opposite to the velocity of a body.

\mathbf{F_r' = 12 F}

where:

  • resistive force \mathbf{ F_r'} = 12 F

Recall that;

  • the gravitational potential energy is constant;
  • the kinetic energy at point A from B = U₀

∴

When the particle is launched from B to A, the kinetic energy gained by the particle can be computed as:

  • U = \mathbf{f_r'r}
  • U = 12 F × r
  • U = 12 U₀  

Learn more about kinetic energy here:

brainly.com/question/12669551?referrer=searchResults

3 0
3 years ago
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