Well if you didn't you could make mistakes, which would lead ,in the best case, at a fail of the circuit , or if it goes out of control it could be dangerous
for example you have to know that the wires become hot and they loose their abbilitys as connecters(the hotter it will, the more energy you lose becouse the R will be bigger)
A fire spreads by transferring heat in 3 ways, Raditation, convection, and Conduction :)
Answer:
E₄ = - 0.85 eV
E₂ = - 3.4 eV
Ephoton = 2.55 eV
Explanation:
The sum of Kinetic Energy (K) and Potential Energy (U) of the Helium atom is equal to the total energy of Helium atom in the specified state N. From Bohr's atomic model, the energy of a hydrogen atom in state N is given as:
En = K + U = (-1/n²)(13.6 eV)
a)
Here,
n = 4
Therefore,
E₄ = (-1/4²)(13.6 eV)
<u>E₄ = - 0.85 eV</u>
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b)
Here,
n = 2
Therefore,
E₂ = (-1/2²)(13.6 eV)
<u>E₂ = - 3.4 eV</u>
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c)
The energy of photon emitted in the transition from level 4 to level 2 will be equal to the difference in the energy of both levels:
Ephoton = ΔE = E₄ - E₂
Ephoton = - 0.85 eV - (- 3.4 eV)
<u>Ephoton = 2.55 eV</u>
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Answer:
The basic unit of matter is atoms
Answer:
Explanation:
the resistance of a electrical device
R = V² / P where V is volt and P is power .
The devices are in parallel so same volt will apply on them
So R₁ = 12² / 32.5 = 4.431 ohm
R₂ = 12² / 2 x 10³ = .072 ohm
when they are in series
Common Current in them = 12 / 4.431 + .072
= 2.6649 A
power consumed by first device when they are in series
= current² x resistance
= 2.6649² x 4.431 = 31.46 W
power consumed by other
= 2.6649² x .072 = .511 W