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rusak2 [61]
3 years ago
14

7Dx%2B5%3F" id="TexFormula1" title="What are the domain and range of the function f(x)=\frac{3}{4}x+5?" alt="What are the domain and range of the function f(x)=\frac{3}{4}x+5?" align="absmiddle" class="latex-formula">What are the domain and range of the function
Mathematics
1 answer:
jeka57 [31]3 years ago
8 0
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes.
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May someone please help mee????
Arlecino [84]

Answer:

width of rectangle is 87

Step-by-step explanation:

because perimeter of rectangle = 2(l+w)

3 0
3 years ago
The perimeter of a rectangle is 132 feet and its area is 1080 square feet. find the dimensions
FrozenT [24]
2x + 2y=132

xy=1080

Let x=1080/y

2160/y + 2y=132
2y^2 - 132y +2160=0
2(y^2-66y+1080)=0
2(y-30)(y-33)=0
y=30 or y=33
(36,30) or (30,36)

So... x=30,36 and y=36,30. Either way, the answer is 30 by 36 or 36 by 30. 
5 0
3 years ago
Find the length of the hypotenuse of the right triangle if the width is 60 and hight is 32
GalinKa [24]

Answer:

The hypotenuse is 68

Step-by-step explanation:

To find the length of the hypotenuse of a a right angled triangle, we use the Pythagoras Theorem

c² = a² + b²

where c = hypotenuse, a = height, 32 and b = width, 60

Substitute the value 32 and 60 for a and b respectively in the above formula, and we will have

c² = 32² + 60²

c² =  1024 + 3600

c² = 4624

c = √4624

c = 68

4 0
3 years ago
For the polynomial below, -2 is a zero.
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

please note -2 is not a zero ,it should be 2 is a zero.

by synthetic division

2|  1  4 -10 -4

  |      2  12  4

  |----------------

     1  6   2  | 0

x²+6x+2=0

x=\frac{-6 \pm \sqrt{36-8} }{2} \\or~x=\frac{-6 \pm2\sqrt{7} }{2} \\or ~x=-3\pm \sqrt{7} \\h(x)=(x-2)(x^2+6x+2)=(x-2)(x-3+\sqrt{7} )(x-3-\sqrt{7})

7 0
3 years ago
Round 2.496 to the nearest hundredth
julia-pushkina [17]

Answer:2.50

Step-by-step explanation:

8 0
3 years ago
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