Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
2x+12=64; x=26
Step-by-step explanation:
2x+12=64
2x=52
x=26
Answer:
215 mm
Step-by-step explanation:
1 cm = 10 mm
21.5 cm * (10 mm)/(1 cm) = 215 mm
Answer: 215 mm
Answer:
16
Step-by-step explanation:
Answer:
14x-2 is answer
Step-by-step explanation:
may be this is helpful!
