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AVprozaik [17]
3 years ago
8

You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. Yo

u set your slit spacing at 1.09 mm and place your screen 8.61 m from the slits. Then, you illuminate the slits with your new toy and find on the screen that the tenth bright fringe is 4.53 cm away from the central bright fringe (counted as the zeroth bright fringe). What is your laser's wavelength ???? expressed in nanometers?
Physics
1 answer:
Vitek1552 [10]3 years ago
6 0

Answer:

λ = 5.734 x 10⁻⁷ m = 573.4 nm

Explanation:

The formula of the Young's Double Slit experiment is given as follows:

\Delta x = \frac{\lambda L}{d}\\\\\lambda = \frac{\Delta x d}{L}

where,

λ = wavelength = ?

L = distance between screen and slits = 8.61 m

d = slit spacing = 1.09 mm = 0.00109 m

Δx = distance between consecutive bright fringes = \frac{4.53\ cm}{10} = 0.00453 m

Therefore,

\lambda = \frac{(0.00453\ m)(0.00109\ m)}{8.61\ m}

<u>λ = 5.734 x 10⁻⁷ m = 573.4 nm</u>

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One hundred turns of insulated copper wire are wrapped into a circular coil of crosssectional area 1.20⇥103 m2. The two ends of
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236.3  x 10^-^3 C

Explanation:

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B(0)=1.60T and B(t)=-1.60T

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The current given by resistance and induced emf as

I = ℰ/R

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By converting the current to differential form(the time derivative of charge), we get

\frac{dq}{dt}=  -NdΦ/dtR

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