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JulijaS [17]
3 years ago
14

A car starting from rest (i.e. initial velocity = 0.0 m/s), moves in the positive X-direction with a constant average accelerati

on = 3.1 m/s2 for 7.9 s. What will be its velocity at that time.
Physics
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

Final speed of the car, v = 24.49 m/s

Explanation:

It is given that,

Initial velocity of the car, u = 0

Acceleration, a=3.1\ m/s^2

Time taken, t = 7.9 s

We need to find the final velocity of the car. Let it is given by v. It can be calculated using first equation of motion as :

v=u+at

v=0+3.1\times 7.9

v = 24.49 m/s

So, the final speed of the car is 24.49 m/s. Hence, this is the required solution.

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Name a device that converts mechanical energy into electrical energy.
erma4kov [3.2K]

Answer:

Electric generator is the device that converts mechanical energy into electrical energy

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3 years ago
An airplane flies with a constant speed of 720 km/hr. How long will it take to travel a distance of 1440 km? Please show your wo
choli [55]

Answer:

2 h

Explanation:

Velocity =Distance/time ⇒ time = distance/speed

                                                     = 1440/720

                                                     = 2 h

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How are force and mass related​
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5 0
4 years ago
Un observador se halla a 510m. de una pared. entre el observador y la pared, y a igual distancia de ambos, se realiza un disparo
ch4aika [34]

Answer:

a)    t = 0.75 s,  b)  t = 2.25 s

Explanation:

The speed of sound is constant in a material medium

           v = 340 m / s

we can use the relations of uniform motion to find the time

          v = x / t

          t = x / v

In the exercise, the observer's distance to the wall is indicated d = 510 m, it also indicates that the shot is fired at the midpoint

          x = d / 2

       

a) direct sound the distance from the observer to the screen is

           x = 510/2 = 255 m

           t = 255/340

           t = 0.75 s

b) echo sound.

In this case the sound reaches the wall bounces, the distance is

             x = d / 2 + d

             x = 3/2 d

             x = 3/2 510

             x = 765 m

the time is

              t = x / v

              t = 765/340

              t = 2.25 s

5 0
3 years ago
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
Read 2 more answers
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