Hello!
First one we can use that PE=mgh so we have
4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m
Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have
g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2
Hope this helps. Any questions please ask. Thank you.
Answer:
A) θ = 13.1º , B) E
Explanation:
A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.
In this reference system the only force that we must decompose is the Normal one, let's use trigonometry
sin θ = Nₓ / N
cos θ = / N
Nₓ = N sin θ
Ny = N cos θ
x-axis (radial)
Nₓ = m a
where the acceleration is centripetal
a = v² / R
we substitute
-N sin θ = -m v² / R (1)
the negative sign indicates that the force and acceleration towards the center of the circle
y-axis (Vertical)
Ny - W = 0
N cos θ = mg
N = mg / cos θ
we substitute in 1
mg / cos θ sin θ = m v² / R
g tan θ = v² / R
θ = tan⁻¹ (v² / gR)
we calculate
θ = tan⁻¹ (25² / 9.8 274)
θ = 13.1º
B) when comparing the equations the correct one is E
From Columb's Law which describe the electrostatic interaction.
The formula is given and looks as follows
where:
F is force acting between charges,
q1 - charge one given in columbs,
q2 - charge two given in columbs,
r - distance between charge in meters
k - constant
First, we have to convert out formula to get r.
Now we multiplaty by
both sides of equation
Now we devide both sides by F
Next step is take square root
We have all date, we can subsitute it to our formula
Unlike bacteria, archaea cell walls
do not contain peptidoglycan.
Archaea have different membrane
lipid bonding compared to Bacteria
and Eucarya.
Archaea have different metabolic pathways.
<u><em>Metabolic differences:
</em></u>
Archaea are very metabolically diverse, so
they are hard to generalize.
Archaea do not use glycolysis pathway to
break down glucose (though they do use
similar pathways).
Many archaea do not have functional Kreb’s
cycle pathways (but some do).