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Vlada [557]
3 years ago
12

Which refers to any disturbance that carries energy from one place to another through matter and space?

Physics
2 answers:
Black_prince [1.1K]3 years ago
4 0
I think frequency it sounds like the correct answer but I am not completely sure if I am correct
Cloud [144]3 years ago
4 0

Answer:

A wave

Explanation:

A wave is a disturbance which carries energy from one place to another.

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What is the difference between velocity and speed??
tatiyna
Velocity is a vector quantity i.e. it has both magnitude and direction
Speed is a scalar quantity i.e. it has only magnitude
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A Level is set up midway between two wood hubs that are about 300 ft. apart. The rod reading on hub A is 9.09 ft. and the readin
Zarrin [17]

Answer:

<em>The correct difference is 3.44 ft</em>

Explanation:

The correct difference is given as

D=R_A-R_B

D=9.09-5.65

D=3.44 ft

4 0
3 years ago
How to get a + b on a graph
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The first positively essential requirement is that
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4 years ago
Calculate the energy released by the electron-capture decay of 5727Co. Consider only the energy of the nuclei (ignore the energy
erma4kov [3.2K]

Answer:

Explanation:

⁵⁷Co₂₇  + e⁻¹  =  ²⁷Fe₂₆

mass defect = 56.936296 + .00055 - 56.935399

= .001447 u

equivalent energy

= 931.5 x .001447 MeV

= 1.3479 MeV .

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= .157 MeV .

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5 0
3 years ago
Two cars A and B are 100m apart moving towards each other with
maxonik [38]

Let car A's starting position be the origin, so that its position at time <em>t</em> is

A: <em>x</em> = (40 m/s) <em>t</em>

and car B has position at time <em>t</em> of

B: <em>x</em> = 100 m - (60 m/s) <em>t</em>

<em />

They meet when their positions are equal:

(40 m/s) <em>t</em> = 100 m - (60 m/s) <em>t</em>

(100 m/s) <em>t</em> = 100 m

<em>t</em> = (100 m) / (100 m/s) = 1 s

so the cars meet 1 second after they start moving.

They are 100 m apart when the difference in their positions is equal to 100 m:

(40 m/s) <em>t</em> - (100 m - (60 m/s) <em>t</em>) = 100 m

(subtract car B's position from car A's position because we take car A's direction to be positive)

(100 m/s) <em>t</em> = 200 m

<em>t</em> = (200 m) / (100 m/s) = 2 s

so the cars are 100 m apart after 2 seconds.

3 0
3 years ago
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