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Vlada [557]
3 years ago
12

Which refers to any disturbance that carries energy from one place to another through matter and space?

Physics
2 answers:
Black_prince [1.1K]3 years ago
4 0
I think frequency it sounds like the correct answer but I am not completely sure if I am correct
Cloud [144]3 years ago
4 0

Answer:

A wave

Explanation:

A wave is a disturbance which carries energy from one place to another.

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Suppose you increase your walking speed from 6 m/s to 15m/s in a period of 3 seconds what is your acceleration
choli [55]
Avg acceleration; under constant acceleration condition only; = Vf-Vi/time
a=Vf-Vi/time=(15m/s-6m/s)/(3s)=
(9m/s)/(3s)=3m/s^2

Hope this helps. Thanks.
7 0
3 years ago
An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?
givi [52]
Divide the objects mass by its volume. 50.0g / 10.5cm^3 =4.76cm ^3
8 0
3 years ago
A 30 kg girl and a 25 kg boy face each other on friction-free roller skates. The girl pushes the boy, who moves away at a speed
Dovator [93]

Answer: 4m/s

Explanation:

Mass of girl = m1 = 30kg

Mass of boy = m2 = 25kg

Resultant speed after collision = 1.0m/s

Speed of girl = v1

Speed of boy = v2

Momentum = mass × velocity

m1v1 - m2v2 = mv

30v1 - 25v2 = 1×m

30v1 - 25v2 = m

v1 = (m + 25v2)/30 ...eqn 1

but m1 - m2 = m

m = 30 - 25 = 5kg

v1 = (5 + 25v2)/30 ...eqn 2

v1-v2 = 1m/s

v2 = (v1 - 1)m/s

Substitute for v2 in eqn 2

v1 = [5 + 25(v1 - 1)]/30

30v1 = 5 + 25v1 - 25

30v1 - 25v1 = -20

5v1 = -20

v1 = -4m/s

Because she moved in an opposite direction to the boy, the negative sign is featured on her speed

3 0
3 years ago
1. What are examples of muscle endurance activities/exercises? 2. Which sports require the most muscle endurance? 3. How many si
Komok [63]

Answer:

hello i need points i need to pass 8th grade

Explanation:

4 0
3 years ago
Read 2 more answers
A pendulum is made of a small sphere of mass 0.250 kg attached to a lightweight string 1.20 m in length. As the pendulum swings
forsale [732]

Answer:v=2 m/s

Explanation:

Given

Length of string L=1.2 m

mass of pendulum m=0.25 kg

maximum inclination with vertical \theta =34

vertical Rise of Pendulum from its mean position  is given by

\Delta h=L(1-\cos \theta )

Conserving Energy at top and bottom point

Potential Energy of sphere is converted into kinetic energy of sphere

mgL(1-\cos \theta )=\frac{mv^2}{2}

v=\sqrt{2gL(1-\cos \theta )}

v=\sqrt{2\times 9.8\times 1.2(1-\cos 34)}

v=\sqrt{4.021}

v=2 m/s

5 0
3 years ago
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