Answer:
zeroIt(&x);
Explanation:
The statement that sets the value stored in x to zero by invoking the function zerolt is given below
zeroIt(&x);
The zeroIt function is also given below for better understanding.
void zeroIt(int *x) {
*x = 0;
}
As seen, the function takes an argument with integer variable type, which is a pointer, denoted by the asterisk symbol (*x).
The ampersan sign (&x) is used to access the variable whose value can then be stored.
Answer: 83.17
Explanation:
By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.
It applies specifically to power, and it is defined as follows:
P (dB) = 10 log₁₀ P₁ / P₂
Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.
In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.
Applying the dB definition, we can write the following:
10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92
Solving the logarithmic equation, we can compute X as follows:
X = 10^1.92 = 83.17
X = 83.17
<span>The RAID level 2 could give high
information exchange rates and would be straightforward contrasted with other
Raid levels. Be that as it may, it has a high cost and would need a high rate move
required with a specific end goal to legitimize this cost.</span>
They are based on 10 digits.
I’m not sure.
