The distinction between "computer architecture" and "computer organization" has become very fuzzy, if no completely confused or unusable. Computer architecture was essentially a contract with software stating unambiguously what the hardware does. The architecture was essentially a set of statements of the form "If you execute this instruction (or get an interrupt, etc.), then that is what happens. Computer organization, then, was a usually high-level description of the logic, memory, etc, used to implement that contract: These registers, those data paths, this connection to memory, etc.
Programs written to run on a particular computer architecture should always run correctly on that architecture no matter what computer organization (implementation) is used.
For example, both Intel and AMD processors have the same X86 architecture, but how the two companies implement that architecture (their computer organizations) is usually very different. The same programs run correctly on both, because the architecture is the same, but they may run at different speeds, because the organizations are different. Likewise, the many companies implementing MIPS, or ARM, or other processors are providing the same architecture - the same programs run correctly on all of them - but have very different high - level organizations inside them.
Answer:
12 percent of international news
Explanation:
Just did it
Answer:
The formula used in this question is called the probability of combinations or combination formula.
Explanation:
Solution
Given that:
Formula applied is stated as follows:
nCr = no of ways to choose r objects from n objects
= n!/(r!*(n-r)!)
The Data given :
Menu A : 5 appetizers and 3 main dishes
Menu B : 3 appetizers and 4 main dishes
Total appetizers - 6
Total main dishes - 5
Now,
Part A :
Total ways = No of ways to select menu A + no of ways to select menu B
= (no of ways to select appetizers in A)*(no of ways to select main dish in A) + (no of ways to select appetizers in B)*(no of ways to select main dish in B)
= 6C5*5C3 + 6C3*5C4
= 6*10 + 20*5
= 160
Part B :
Since, we can select the same number of appetizers/main dish again so the number of ways to select appetizers/main dishes will be = (total appetizers/main dishes)^(no of appetizers/main dishes to be selected)
Total ways = No of ways to select menu A + no of ways to select menu B
= (no of ways to select appetizers in A)*(no of ways to select main dish in A) + (no of ways to select appetizers in B)*(no of ways to select main dish in B)
= (6^5)*(5^3) + (6^3)*(5^4)
= 7776*125 + 216*625
= 1107000
Part C :
No of ways to select same appetizers and main dish for all the options
= No of ways to select menu A + no of ways to select menu B
= (no of ways to select appetizers in A)*(no of ways to select main dish in A) + (no of ways to select appetizers in B)*(no of ways to select main dish in B)
=(6*5) + (6*5)
= 60
Total ways = Part B - (same appetizers and main dish selected)
= 1107000 - 60
= 1106940
In desperation, and with the clock ticking down to the must-see Reds v Crusaders game, I gambled on running the 'factory reset' function, then reinstalling all the channels.
Result: success!
Might be a useful tip for anyone else who finds themselves with this problem.
<span>Cheers</span>