Question 5

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

I have to go see my dog in the hospital today

You might be interested in

Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

6 0

3 years ago

Read 2 more answers

2. G(x) = 2x² + 3x<br>Is the function even, odd, or neither?

Bingel [31]

The function appears to be neither odd nor even

8 0

3 years ago

If a polynomial function f(x) has roots 3 and square root of 7, what must also be a root of f(x)

Neko [114]

Answer:

x = - $\sqrt{7}$

Step-by-step explanation:

Radical roots occur in pairs, that is

x = $\sqrt{7}$ is a root then so is x = - $\sqrt{7}$

3 0

3 years ago

Read 2 more answers

How many 16th notes = a half note?

Ber [7]

Answer:

hi so read explanation

Step-by-step explanation:

four sixteenth notes

Four eighth notes equal one- half note in duration and eight eighth notes equal one whole note. Two sixteenth notes are to equal one- eighth note in duration and four sixte enth notes equal one- quarter note in durations. hope dis helped

4 0

3 years ago

Three parallel intersects an east west street at right angles. Name the east west street

ololo11 [35]

You need a map or a picture of what you are talking about so i can help find you the answer so please take a picture and post it so i can see it.

8 0

3 years ago