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frozen [14]
3 years ago
13

Question 5

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
I have to go see my dog in the hospital today
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a recipe for cookies calls for 10 1/6 cups of sugar. krystal has already put in 4 2/3 cups. how many more cups does she need to
DENIUS [597]

Answer:

5 1/2 cups

Step-by-step explanation:

10 1/6 = \frac{61}{6} cups

10 x 6 + 1

\frac{61}{6}

4 2/3 = \frac{14}{3} cups

4 x 3 + 2

\frac{14}{3}

Find a common denominator (6)

\frac{14}{3} = \frac{28}{6}

\frac{14}{3} · 2 = \frac{28}{6}

\frac{61}{6} - \frac{28}{6} = \frac{33}{6}

\frac{33}{6} or 5 1/2 cups

6 0
3 years ago
Giving out 16 points if you can help me :))
Paraphin [41]

Answer:

g(x)=-6x+5

Step-by-step explanation:

3 0
3 years ago
How do i multiply ?​
attashe74 [19]

Answer:

Do repeated addition

Step-by-step explanation:

For example 12 * 12 = 144 because 12+12+12+12+12+12+12+12+12+12+12+12=144

7 0
3 years ago
Which expression represents the perimeter of the
Svetllana [295]
Answer: 15x + 6
5x + 2x+3 = 7x+3
6x+4 + 7x+3 = 13x + 7
13x+7 + 2x-1 = 15x+ 6
5 0
3 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
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