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3 years ago

Question 5

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

I have to go see my dog in the hospital today

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a recipe for cookies calls for 10 1/6 cups of sugar. krystal has already put in 4 2/3 cups. how many more cups does she need to

DENIUS [597]

Answer:

5 1/2 cups

Step-by-step explanation:

10 1/6 = $\frac{61}{6} cups$

10 x 6 + 1

$\frac{61}{6}$

4 2/3 = $\frac{14}{3} cups$

4 x 3 + 2

$\frac{14}{3}$

Find a common denominator (6)

$\frac{14}{3} = \frac{28}{6}$

$\frac{14}{3}$ · 2 = $\frac{28}{6}$

$\frac{61}{6} - \frac{28}{6} = \frac{33}{6}$

$\frac{33}{6}$ or 5 1/2 cups

6 0

3 years ago

Giving out 16 points if you can help me :))

Paraphin [41]

Answer:

g(x)=-6x+5

Step-by-step explanation:

3 0

3 years ago

How do i multiply ?

attashe74 [19]

Answer:

Do repeated addition

Step-by-step explanation:

For example 12 * 12 = 144 because 12+12+12+12+12+12+12+12+12+12+12+12=144

7 0

3 years ago

Which expression represents the perimeter of the

Svetllana [295]

Answer: 15x + 6
5x + 2x+3 = 7x+3
6x+4 + 7x+3 = 13x + 7
13x+7 + 2x-1 = 15x+ 6

5 0

3 years ago

Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

7 0

2 years ago