Answer:
C. T is not one-to-one because the standard matrix A has a free variable.
Step-by-step explanation:
Given
Required
Determine if it is linear or onto
Represent the above as a matrix.
![T(x_1,x_2,x_3) = \left[\begin{array}{ccc}1&-5&4\\0&1&-6\\0&0&0\end{array}\right] \left[\begin{array}{c}x_1&x_2&x_3\end{array}\right]](https://tex.z-dn.net/?f=T%28x_1%2Cx_2%2Cx_3%29%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-5%264%5C%5C0%261%26-6%5C%5C0%260%260%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%26x_2%26x_3%5Cend%7Barray%7D%5Cright%5D)
From the above matrix, we observe that the matrix does not have a pivot in every column.
This means that the column are not linearly independent, & it has a free variable and as such T is not one-on-one
Please enclose that -3/5 in parentheses: <span>y+1= (−3/5)(x−4)
</span>
Let's use the intercept method to graph this line.
First, set x = 0 and find y; this y will be the y-coordinate of the vertical intercept:
y+1= (−3/5)(0−4) => y = -1 + 12/5 = -5/5 + 12/5 = 7/5. Plot (0, 7/5).
Next, set y = 0 and find x; this will give us the coordinate of the horiz. int.:
0+1= (−3/5)(x−4) => -5/3 = x - 4, or x = 4- 5/3, or x = 7/3. Plot (7/3, 0).
Now draw a straight line thru these two points.
A OK this was hard very hard
Answer:
A.12
Step-by-step explanation:
2×r-13 = 11
r + 2 = 14
11 + 14 = 25
Answer:
Step-by-step explanation:
Given that :
The enormous sinkhole that appeared in the middle of Guatemalan neighborhood in the year 2010 swallowed a three story building above it and the sinkhole has an estimated depth of about 100 feet
How much material is needed to fill the sinkhole?
Then , the material needed to fill the sinkhole will be dependent on the volume of the sinkhole.
Determine what information is needed to answer the question.
The information that is needed to answer this question are:
the base area of the sinkhole will be required; &
the height should also be known
if the base area is determined then we can proceed to determine how much material is needed to be calculated.
Do you think your estimate is more likely to be too high or too low
No, the estimate is not likely to be too high or too low rather the estimate of the material required will be almost equal to the volume of the sinkhole, but that does not implies that it will be exactly the same since the sinkhole is not uniform and regular in shape.
