Answer:
The equation of the line would be y = -2x + 7
Step-by-step explanation:
In order to solve this, use the point and the slope in point-slope form. Then solve for y.
y - y1 = m(x - x1)
y - 5 = -2(x - 1)
y - 5 = -2x + 2
y = -2x + 7
Answer:
5,6241
Step-by-step explanation:
I have no idea if this is correct but I hope it is. I hope this helps.
8 is the answer to your question
the answer is d
hope this helps
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
