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zalisa [80]
3 years ago
9

What was the vertical component of her acceleration during push-off? the positive direction is upward?

Physics
1 answer:
gladu [14]3 years ago
5 0
<span>The answer of these two problems are : A) a = (F-W)/m = (100-500)/500/g = 9.8*500/500 = +9.8 m/sec^2 B) a1 = +9.8-g = 0</span>
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I believe its B ,<span> (the direction the north end of a </span>compass<span> needle points, corresponding to the direction of the Earth's </span>magnetic<span> field lines)</span>
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Sand is pouring out of a pipe and is forming a conical pile on the ground. The radius of the pile is increasing at a rate of 2 f
Anton [14]

Answer:

a)\ V=3053.628059 \ ft^3

b)\ V'=1017.876\ ft^3/day

Explanation:

<u>Rate of Change</u>

The volume of a cone of radius r and height h is given by

\displaystyle V=\frac{\pi r^2h}{3}

The height is said to be 1/2 of the radius, thus

\displaystyle V=\frac{\pi r^2\cdot r}{2\cdot 3}

\displaystyle V=\frac{\pi r^3}{6}

a) Knowing r=18 feet, the volume is

\displaystyle V=\frac{\pi 18^3}{6}

V=3053.628059 \ ft^3

b) The rate of change of the volume is computed by taking the derivative of both sides respect to the time

\displaystyle V'=3\frac{\pi r^2}{6}r'

\displaystyle V'=\frac{\pi r^2}{2}r'

Where r' is the given rate of change of the radius: 2 feet/day.

Now we compute

\displaystyle V'=\frac{\pi 18^2}{2}\cdot 2=1017.876

\boxed{V'=1017.876\ ft^3/day}

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Explanation:

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