Answer:
Option 3: -48 cm
Explanation:
We are given:
refractive index; n = 1.5
radius of curvature; r2 = 24 cm
Formula for the focal length is given as;
1/f = (n - 1) × [(1/r1) - (1/r2)]
As r1 tends to infinity, 1/r1 = 0
Thus,we now have;
1/f = (n - 1) × (-1/r2)
Plugging in the relevant values;
1/f = (1.5 - 1) × (-1/24)
1/f = -0.02083333333
f = -1/0.02083333333
f = -48 cm
Answer:
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For example, a trade secret may<span> be a confidential device, pattern, </span>information<span>, or </span>chemical<span> make-up.</span>Chemical industry<span> trade secrets are generally formulas, process data, or a "specific </span>chemical<span> identity." The latter is the type of trade secret </span>information<span> referred to in the Hazard Communication Standard. The term includes</span>
Answer:
The magnitude of the electric force on a protein with this charge is 
Explanation:
Given that,
Electric field = 1500 N/C
Charge = 30 e
We need to calculate the magnitude of the electric force on a protein with this charge
Using formula of electrostatic force

Where, F = force
E = electric field
q = charge
Put the value into the formula


Hence, The magnitude of the electric force on a protein with this charge is 