Answer:
The pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²
Explanation:
Given;
mass of the woman, m = 55 kg
diameter of the circular heel, d = 6.0 mm
radius of the heel, r = 3.0 mm = 0.003 m
Cross-sectional area of the heel is given by;
A = πr²
A = π(0.003)²
A = 2.8278 x 10⁻⁵ m²
The weight of the woman is given by;
W = mg
W = 55 x 9.8
W = 539 N
The pressure exerted by the woman on the floor is given by;
P = F / A
P = W / A
P = 539 / (2.8278 x 10⁻⁵ )
P = 1.9061 x 10⁷ N/m²
Therefore, the pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²
Explanation:
Could you also show the diagram
Answer:
hello your question is poorly written and I have tried to understand it hence I will give a general diagram as related to your question
answer : attached below
Explanation:
Attached below is the required diagram of the situation you are trying to describe
let the wide receiver be ; W
Corner back = C
westward velocity = Vw
eastward velocity = Vc
at initial position X = Xw
x = 0 ( initial position )
Answer:
Explanation:
Magnetic field due to a long current carrying conductor
μ₀ / 4π x 2i / r ( i = current , r = distance of point from wire )
= 10⁻⁷ x 2 x 120 / 6.4 ( i = 120 A , r = 6.4m )
= 37.5 x 10⁻⁷ T .
= 3. 75 X 10⁻⁶ T .
= 3.75 µT.
b )
The direction of this field will be horizontal hence it will affect magnetic needle.
