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algol [13]
3 years ago
7

Why does a stream or river change direction when going down a steep mountain

Physics
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

gravity

Explanation:

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What mission is underway to observe pluto?
liubo4ka [24]

The answer is; NASA's New Horizons spacecraft

It was launched in 2006 from Cape Canaveral and engineered by the Johns Hopkins University. The spacecraft has flown past Pluto, collected data and is now exploring the Kuiper belt object. The mission involved mapping of the planet's surface and check for atmosphere.

5 0
3 years ago
If there are 50 grams of U-238 on day zero of radioactive decay, how much will there be after 4.5 billion years
snow_lady [41]
We use the formula of the half-life to calculate for the remaining U-238 after 4.5 billion years. The formula is expressed as A = A₀ (1/2)^(t/h) where A is the final amount, A₀ is the initial amount of the substance, t is the time and h is the half-life of the substance wherein for U-238 h is equal to 4.47 billion years.

<span>A = A₀ (1/2)^(t/h)
</span>A = 50 (1/2)^(4.5 / 4.47)
A = 24.88 g
4 0
3 years ago
Read 2 more answers
four forces act on an object of mass 100kg, they are 12N(N), 70N(S), 33N(E), 10N(w). calculate the reseulting acceleration of th
trapecia [35]

Answer:

0.62 m/s² at 68° S of E

Explanation:

Net force north = 12 - 70 = -58 N

Net force east = 33 - 10 = 23 N

Net force = √(-58² + 23²) = 62.3939... N

acceleration = F/m = 62.3939/100 = 0.623939... ≈ 0.62 m/s²

θ = arctan(-58/23) = -68.3691... ≈ 68° S of E

6 0
3 years ago
The position of a 2.2 kg mass is given by x=(2t3â5t2) m, where t is in seconds.
Juliette [100K]
B b b b b b b bb  bb   bb b b b b b b b b b 
6 0
3 years ago
A block of weight mg sits on an inclined plane as shown in (Figure 1) . A force of magnitude F1 is applied to pull the block up
svlad2 [7]

Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

Y Axis  

       N - W_{y} =

       N = W_{y}

X axis

       F1 - fr - Wₓ = 0

       fr = F1 - Wₓ

Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     cos θ = W_{y} / W

      Wₓ = W sin θ

      W_{y} = W cos θ

We substitute

      fr = F1 - W sin θ

Work is defined by

        W = F .dx

        W = F dx cos θ

The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

4 0
3 years ago
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