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Cloud [144]
3 years ago
5

Write an equation that expresses the following relationship. u varies jointly with p and d and inversely with w In your equation

, use k as the constant of proportionality.
Physics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
<h2>Answer:</h2>

\boxed{y=k\frac{pd}{w}}

<h2>Explanation:</h2>

Let's explain what direct and indirect variation mean:

  • When we say that y varies jointly as x \ and \ w, we mean that:

y=kxw for some nonzero constant k that is the constant of variation or the constant of proportionality.

  • On the other hand, when we say that y varies inversely as x or y is inversely proportional to x, we mean that:

y=\frac{k}{x} for some nonzero constant k, where k is also the constant of variation.

___________________

In this problem, u varies jointly with p and d and inversely with w, being k the constant of proportionality, then:

\boxed{y=k\frac{pd}{w}}

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Find the average energy E for (a) An n-state system, in which a given state can have energy 0,,2,...,n . (b) A harmonic oscillat
kicyunya [14]

Answer:

a♦1  E_average = n E₀ / 2 , b) E_average= infinity

Explanation:

The energy values ​​form an arithmetic series, whose sum is

          S = n (a₁ + aₙ) / 2 = n (2a₁ + (n-1) r)/ 2

Where n is the number of terms, a₁ is the first term, aₙ the last term and r is the difference between two consecutive numbers in the series

          r = 2E₀ - 0 = 2E₀

Therefore the sum is

       S = n (0 + n E₀) / 2

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The average value is

         E_average = S / n

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b) the case of harmonic oscillation

We have two possibilities.

- if we take a finite number and terms gives the same previous value

- If we take an infinite number of fears the series gives infinity and the average is also infinite

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4 0
3 years ago
The critical angle for a special type of glass in air is 30.8 ◦ . the index of refraction for water is 1.33. what is the critica
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When light moves from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle above which there is no refracted light, and all the light is reflected. The value of this angle is given by
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where n2 and n1 are the refractive indices of the second and first medium, respectively.

In the first part of the problem, light moves from glass to air (n_a=1.00) and the critical angle is \theta_c = 30.8^{\circ}. This means that we can find the refractive index of glass by re-arranging the previous formula:
n_g=n_1 =  \frac{n_2}{\sin \theta_c}= \frac{1.00}{\sin 30.8^{\circ}}=1.95

Now the glass is put into water, whose refractive index is n_w = 1.33. If light moves from glass to water, the new critical angle will be
\theta_c = \arcsin ( \frac{n_2}{n_1} )=\arcsin( \frac{n_w}{n_g} )=\arcsin( \frac{1.33}{1.95} )=\arcsin(0.68)=43.0^{\circ}
6 0
3 years ago
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