Answer:
Objects move according to their net force, or the total amount of force acting on them. Balanced forces are just that, balanced. An object with balanced forces will not move because the opposing forces will cancel each other out. However, if there are unbalanced forces, the object will move in accordance with the force that is greater. When moving though, there is always friction. Whether you be underwater, on the ground, or in the air there is always friction on the Earth. (Besides vacuums, of course.)
Force is equal to mass x acceleration.
With that you can find the forces of the object if you know its mass and acceleration.
Explanation:
The motion of an object can be described in many ways, including path, speed, velocity, and acceleration.
It’s important for a scientist to be open-minded because they need to be able to understand or creative anything that was never thought about. It’s also important for a scientist to be skeptical because some ideas or products that they hear about can have false factors. I hope this helped!
Answer:
compass needle normally points toward Earth's magnetic pole, which is near the North Pole. Which best explains why the
eedle moves away from the pole when it comes close to a current-carrying wire?
Current within the wire weakens the magnetic force of the pole.
Magnetism surrounding the wire weakens the magnetic force of the nole
Explanation:
The Lorentz force exerted on the particle due to the magnetic field provides the centripetal force that keeps the particle in circular motion:
![m \frac{v^2}{r} = qvB](https://tex.z-dn.net/?f=m%20%5Cfrac%7Bv%5E2%7D%7Br%7D%20%3D%20qvB)
where
m is the particle mass
v is its velocity
r its orbital radius
q its charge
B the magnetic field intensity
and where we neglected the factor
![\sin \theta](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta)
in the Lorentz force formula because the particle is traveling perpendicular to the magnetic field, so
![\sin \theta=1](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D1)
.
Re-arranging the formula, we get
![r= \frac{mv}{qB}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7Bmv%7D%7BqB%7D%20)
(1)
The problem gives us all the data about the particle and the magnetic field:
![m=2.05 pg= 2.05 \cdot 10^{-12} g=2.05 \cdot 10^{-15} kg](https://tex.z-dn.net/?f=m%3D2.05%20pg%3D%202.05%20%5Ccdot%2010%5E%7B-12%7D%20g%3D2.05%20%5Ccdot%2010%5E%7B-15%7D%20kg)
![v=67.3 km/s = 67.3 \cdot 10^3 m/s](https://tex.z-dn.net/?f=v%3D67.3%20km%2Fs%20%3D%2067.3%20%5Ccdot%2010%5E3%20m%2Fs)
![q=3.32 \mu C = 3.32 \cdot 10^{-6} C](https://tex.z-dn.net/?f=q%3D3.32%20%5Cmu%20C%20%3D%203.32%20%5Ccdot%2010%5E%7B-6%7D%20C)
(we are only interested in the magnitude of the charge)
![B=7.85 mT = 7.85 \cdot 10^{-3}T](https://tex.z-dn.net/?f=B%3D7.85%20mT%20%3D%207.85%20%5Ccdot%2010%5E%7B-3%7DT)
And by plugging these numbers into eq.(1), we find the radius of the orbit