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jonny [76]
3 years ago
11

Scientists observe an approaching asteroid that is on a collision course with

Physics
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

The approximate velocity the rocket must have to stop the asteroid completely after the collision is;

C. -324 m/s

Explanation:

The parameters of the asteroid and the rocket are;

The mass of the asteroid, m₁ = 11,000 kg

The initial velocity with which the asteroid is approaching Earth, v₁ = 50 m/s

The mass of the rocket, m₂ = 1700 kg

The initial velocity of the rocket = v₂

The final velocity of the combined asteroid and rocket after the collision, v₃ = 0 m/s

By the law of conservation of linear momentum, we have;

The total initial momentum = The total final momentum

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Substituting the known values, we get;

11,000 kg × 50 m/s + 1,700 kg × v₂ = (11,000 kg + 1,700 kg) × 0 m/s

11,000 kg × 50 m/s + 1,700 kg × v₂ = 0

∴ 1,700 kg × v₂ = -11,000 kg × 50 m/s

v₂ = (-11,000 kg × 50 m/s)/(1,700 kg) = -323.529412 m/s ≈ -324 m/s

The approximate initial velocity the jet must have to completely stop the asteroid after the collision is -324 m/s.

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A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At
Pani-rosa [81]

The distance covered is 1000 m

Explanation:

The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

s=vt-\frac{1}{2}at^2

where

s is the distance covered

v is the final velocity

t is the time

a is the acceleration

For the rocket in this problem, we have:

v = 445 m/s is the final velocity

a=99.0 m/s^2 is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m

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8 0
4 years ago
A group of workers applied 10.0 networks of force to move a crate 20.0 meter. Calculate the work
olga2289 [7]

The work done is 200 J

Explanation:

The work done by a force applied to move an object is given by:

W= F d cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, assuming that the force applied by the workers is parallel to the direction of motion of the crate, we have:

F = 10.0 N

d = 20.0 m

\theta=0^{\circ}

Therefore, the work done is:

W=(10.0)(20.0)(cos 0)=200 J

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4 0
4 years ago
In a previous problem, you calculated how much energy was needed to accelerate a 2,100-kg Tesla Model S from 0 to 100 km/hr, and
Naddika [18.5K]

Answer:

t=2.348s

Explanation:

First we need to calculate the Potential Energy of a Tesla to reach the 100km/h

So we know that,

W=KE_f - KE_i = \frac{1}{2}m(V_f^2-V_i^2)=\frac{1}{2}(2100)(27.78^2)W=8.1*10^5J

Here we can to calculate the time through,

t=\frac{W}{P}

t=\frac{8.1*10^5}{345*10^3}

t=2.348s

5 0
3 years ago
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