Answer:
The magnitude of the tension on the ends of the clothesline is 41.85 N.
Explanation:
Given that,
Poles = 2
Distance = 16 m
Mass = 3 kg
Sags distance = 3 m
We need to calculate the angle made with vertical by mass
Using formula of angle



We need to calculate the magnitude of the tension on the ends of the clothesline
Using formula of tension

Put the value into the formula


Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.
Answer:
i dont know why are u asking me
Explanation:
Answer to<span> A farm </span>truck moves<span> due east with a </span>constant<span> velocity of 9.50 m/s on a limitless, horizontal stretch on the back of the </span>t<span>... ... (b) what is the initial </span>speed<span> of the </span>can<span> relative </span>to<span> the </span>truck<span>? ... the </span>time<span> of flight of the </span>can<span> by considering its horizontal motion x = x_o+ v_ot + (1/2)at^2 ... Expert answers in as little as 30 </span>minutes<span>.</span>
Answer: 1.51 km
Explanation:
<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.
Or, 
Where Q1 and Q2 are magnitude of two charges and r is distance between them:
<u>Given:</u>
Q1 = Charge near top of cloud = 48.8 C
Q2 = Charge near the bottom of cloud = -41.7 C
Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N
k = 8.99 x 109Nm^2/C^2
<u>So,</u>

Therefore, the separation between the two charges (r) = 1.51 km